2nd(cons1(

2nd(cons(

from(

R

↳Dependency Pair Analysis

2ND(cons(X,X1)) -> 2ND(cons1(X,X1))

FROM(X) -> FROM(s(X))

Furthermore,

R

↳DPs

→DP Problem 1

↳Remaining Obligation(s)

The following remains to be proven:

**FROM( X) -> FROM(s(X))**

2nd(cons1(X, cons(Y,Z))) ->Y

2nd(cons(X,X1)) -> 2nd(cons1(X,X1))

from(X) -> cons(X, from(s(X)))

Duration:

0:00 minutes