R
↳Dependency Pair Analysis
F(x, c(y)) -> F(x, s(f(y, y)))
F(x, c(y)) -> F(y, y)
F(s(x), s(y)) -> F(x, s(c(s(y))))
R
↳DPs
→DP Problem 1
↳Argument Filtering and Ordering
→DP Problem 2
↳AFS
F(s(x), s(y)) -> F(x, s(c(s(y))))
f(x, c(y)) -> f(x, s(f(y, y)))
f(s(x), s(y)) -> f(x, s(c(s(y))))
F(s(x), s(y)) -> F(x, s(c(s(y))))
f(x, c(y)) -> f(x, s(f(y, y)))
f(s(x), s(y)) -> f(x, s(c(s(y))))
POL(c) = 0 POL(s(x1)) = 1 + x1 POL(F(x1, x2)) = x1 + x2
F(x1, x2) -> F(x1, x2)
s(x1) -> s(x1)
c(x1) -> c
f(x1, x2) -> x1
R
↳DPs
→DP Problem 1
↳AFS
→DP Problem 3
↳Dependency Graph
→DP Problem 2
↳AFS
f(x, c(y)) -> f(x, s(f(y, y)))
f(s(x), s(y)) -> f(x, s(c(s(y))))
R
↳DPs
→DP Problem 1
↳AFS
→DP Problem 2
↳Argument Filtering and Ordering
F(x, c(y)) -> F(y, y)
f(x, c(y)) -> f(x, s(f(y, y)))
f(s(x), s(y)) -> f(x, s(c(s(y))))
F(x, c(y)) -> F(y, y)
f(x, c(y)) -> f(x, s(f(y, y)))
f(s(x), s(y)) -> f(x, s(c(s(y))))
POL(c(x1)) = 1 + x1 POL(s(x1)) = x1
F(x1, x2) -> x2
c(x1) -> c(x1)
f(x1, x2) -> x1
s(x1) -> s(x1)
R
↳DPs
→DP Problem 1
↳AFS
→DP Problem 2
↳AFS
→DP Problem 4
↳Dependency Graph
f(x, c(y)) -> f(x, s(f(y, y)))
f(s(x), s(y)) -> f(x, s(c(s(y))))