Term Rewriting System R:
[x]
f(s(0), g(x)) -> f(x, g(x))
g(s(x)) -> g(x)
Termination of R to be shown.
R
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
F(s(0), g(x)) -> F(x, g(x))
G(s(x)) -> G(x)
Furthermore, R contains two SCCs.
R
↳DPs
→DP Problem 1
↳Polynomial Ordering
→DP Problem 2
↳FwdInst
Dependency Pair:
G(s(x)) -> G(x)
Rules:
f(s(0), g(x)) -> f(x, g(x))
g(s(x)) -> g(x)
The following dependency pair can be strictly oriented:
G(s(x)) -> G(x)
There are no usable rules w.r.t. to the implicit AFS that need to be oriented.
Used ordering: Polynomial ordering with Polynomial interpretation:
POL(G(x1)) | = x1 |
POL(s(x1)) | = 1 + x1 |
resulting in one new DP problem.
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 3
↳Dependency Graph
→DP Problem 2
↳FwdInst
Dependency Pair:
Rules:
f(s(0), g(x)) -> f(x, g(x))
g(s(x)) -> g(x)
Using the Dependency Graph resulted in no new DP problems.
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Forward Instantiation Transformation
Dependency Pair:
F(s(0), g(x)) -> F(x, g(x))
Rules:
f(s(0), g(x)) -> f(x, g(x))
g(s(x)) -> g(x)
On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule
F(s(0), g(x)) -> F(x, g(x))
one new Dependency Pair
is created:
F(s(0), g(s(0))) -> F(s(0), g(s(0)))
The transformation is resulting in one new DP problem:
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳FwdInst
→DP Problem 4
↳Remaining Obligation(s)
The following remains to be proven:
Dependency Pair:
F(s(0), g(s(0))) -> F(s(0), g(s(0)))
Rules:
f(s(0), g(x)) -> f(x, g(x))
g(s(x)) -> g(x)
Termination of R could not be shown.
Duration:
0:00 minutes