f(g(

g(s(

g(0) -> 0

R

↳Dependency Pair Analysis

F(g(x), s(0)) -> F(g(x), g(x))

G(s(x)) -> G(x)

Furthermore,

R

↳DPs

→DP Problem 1

↳Polynomial Ordering

→DP Problem 2

↳Remaining

**G(s( x)) -> G(x)**

f(g(x), s(0)) -> f(g(x), g(x))

g(s(x)) -> s(g(x))

g(0) -> 0

The following dependency pair can be strictly oriented:

G(s(x)) -> G(x)

Additionally, the following rules can be oriented:

f(g(x), s(0)) -> f(g(x), g(x))

g(s(x)) -> s(g(x))

g(0) -> 0

Used ordering: Polynomial ordering with Polynomial interpretation:

_{ }^{ }POL(0)= 0 _{ }^{ }_{ }^{ }POL(g(x)_{1})= x _{1}_{ }^{ }_{ }^{ }POL(G(x)_{1})= x _{1}_{ }^{ }_{ }^{ }POL(s(x)_{1})= 1 + x _{1}_{ }^{ }_{ }^{ }POL(f(x)_{1}, x_{2})= 0 _{ }^{ }

resulting in one new DP problem.

R

↳DPs

→DP Problem 1

↳Polo

→DP Problem 3

↳Dependency Graph

→DP Problem 2

↳Remaining

f(g(x), s(0)) -> f(g(x), g(x))

g(s(x)) -> s(g(x))

g(0) -> 0

Using the Dependency Graph resulted in no new DP problems.

R

↳DPs

→DP Problem 1

↳Polo

→DP Problem 2

↳Remaining Obligation(s)

The following remains to be proven:

**F(g( x), s(0)) -> F(g(x), g(x))**

f(g(x), s(0)) -> f(g(x), g(x))

g(s(x)) -> s(g(x))

g(0) -> 0

Duration:

0:00 minutes