Term Rewriting System R:
[X, Y, X1, X2]
fact(X) -> if(zero(X), ns(n0), nprod(X, nfact(np(X))))
fact(X) -> nfact(X)
add(0, X) -> X
add(s(X), Y) -> s(add(X, Y))
prod(0, X) -> 0
prod(s(X), Y) -> add(Y, prod(X, Y))
prod(X1, X2) -> nprod(X1, X2)
if(true, X, Y) -> activate(X)
if(false, X, Y) -> activate(Y)
zero(0) -> true
zero(s(X)) -> false
p(s(X)) -> X
p(X) -> np(X)
s(X) -> ns(X)
0 -> n0
activate(ns(X)) -> s(activate(X))
activate(n0) -> 0
activate(nprod(X1, X2)) -> prod(activate(X1), activate(X2))
activate(nfact(X)) -> fact(activate(X))
activate(np(X)) -> p(activate(X))
activate(X) -> X
Termination of R to be shown.
R
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
FACT(X) -> IF(zero(X), ns(n0), nprod(X, nfact(np(X))))
FACT(X) -> ZERO(X)
ADD(s(X), Y) -> S(add(X, Y))
ADD(s(X), Y) -> ADD(X, Y)
PROD(s(X), Y) -> ADD(Y, prod(X, Y))
PROD(s(X), Y) -> PROD(X, Y)
IF(true, X, Y) -> ACTIVATE(X)
IF(false, X, Y) -> ACTIVATE(Y)
ACTIVATE(ns(X)) -> S(activate(X))
ACTIVATE(ns(X)) -> ACTIVATE(X)
ACTIVATE(n0) -> 0'
ACTIVATE(nprod(X1, X2)) -> PROD(activate(X1), activate(X2))
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X1)
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X2)
ACTIVATE(nfact(X)) -> FACT(activate(X))
ACTIVATE(nfact(X)) -> ACTIVATE(X)
ACTIVATE(np(X)) -> P(activate(X))
ACTIVATE(np(X)) -> ACTIVATE(X)
Furthermore, R contains three SCCs.
R
↳DPs
→DP Problem 1
↳Size-Change Principle
→DP Problem 2
↳SCP
→DP Problem 3
↳Inst
Dependency Pair:
ADD(s(X), Y) -> ADD(X, Y)
Rules:
fact(X) -> if(zero(X), ns(n0), nprod(X, nfact(np(X))))
fact(X) -> nfact(X)
add(0, X) -> X
add(s(X), Y) -> s(add(X, Y))
prod(0, X) -> 0
prod(s(X), Y) -> add(Y, prod(X, Y))
prod(X1, X2) -> nprod(X1, X2)
if(true, X, Y) -> activate(X)
if(false, X, Y) -> activate(Y)
zero(0) -> true
zero(s(X)) -> false
p(s(X)) -> X
p(X) -> np(X)
s(X) -> ns(X)
0 -> n0
activate(ns(X)) -> s(activate(X))
activate(n0) -> 0
activate(nprod(X1, X2)) -> prod(activate(X1), activate(X2))
activate(nfact(X)) -> fact(activate(X))
activate(np(X)) -> p(activate(X))
activate(X) -> X
We number the DPs as follows:
- ADD(s(X), Y) -> ADD(X, Y)
and get the following Size-Change Graph(s):
which lead(s) to this/these maximal multigraph(s):
DP: empty set
Oriented Rules: none
We used the order Homeomorphic Embedding Order with Non-Strict Precedence.
trivial
with Argument Filtering System:
s(x1) -> s(x1)
We obtain no new DP problems.
R
↳DPs
→DP Problem 1
↳SCP
→DP Problem 2
↳Size-Change Principle
→DP Problem 3
↳Inst
Dependency Pair:
PROD(s(X), Y) -> PROD(X, Y)
Rules:
fact(X) -> if(zero(X), ns(n0), nprod(X, nfact(np(X))))
fact(X) -> nfact(X)
add(0, X) -> X
add(s(X), Y) -> s(add(X, Y))
prod(0, X) -> 0
prod(s(X), Y) -> add(Y, prod(X, Y))
prod(X1, X2) -> nprod(X1, X2)
if(true, X, Y) -> activate(X)
if(false, X, Y) -> activate(Y)
zero(0) -> true
zero(s(X)) -> false
p(s(X)) -> X
p(X) -> np(X)
s(X) -> ns(X)
0 -> n0
activate(ns(X)) -> s(activate(X))
activate(n0) -> 0
activate(nprod(X1, X2)) -> prod(activate(X1), activate(X2))
activate(nfact(X)) -> fact(activate(X))
activate(np(X)) -> p(activate(X))
activate(X) -> X
We number the DPs as follows:
- PROD(s(X), Y) -> PROD(X, Y)
and get the following Size-Change Graph(s):
which lead(s) to this/these maximal multigraph(s):
DP: empty set
Oriented Rules: none
We used the order Homeomorphic Embedding Order with Non-Strict Precedence.
trivial
with Argument Filtering System:
s(x1) -> s(x1)
We obtain no new DP problems.
R
↳DPs
→DP Problem 1
↳SCP
→DP Problem 2
↳SCP
→DP Problem 3
↳Instantiation Transformation
Dependency Pairs:
IF(false, X, Y) -> ACTIVATE(Y)
ACTIVATE(np(X)) -> ACTIVATE(X)
ACTIVATE(nfact(X)) -> ACTIVATE(X)
ACTIVATE(nfact(X)) -> FACT(activate(X))
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X2)
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X1)
ACTIVATE(ns(X)) -> ACTIVATE(X)
IF(true, X, Y) -> ACTIVATE(X)
FACT(X) -> IF(zero(X), ns(n0), nprod(X, nfact(np(X))))
Rules:
fact(X) -> if(zero(X), ns(n0), nprod(X, nfact(np(X))))
fact(X) -> nfact(X)
add(0, X) -> X
add(s(X), Y) -> s(add(X, Y))
prod(0, X) -> 0
prod(s(X), Y) -> add(Y, prod(X, Y))
prod(X1, X2) -> nprod(X1, X2)
if(true, X, Y) -> activate(X)
if(false, X, Y) -> activate(Y)
zero(0) -> true
zero(s(X)) -> false
p(s(X)) -> X
p(X) -> np(X)
s(X) -> ns(X)
0 -> n0
activate(ns(X)) -> s(activate(X))
activate(n0) -> 0
activate(nprod(X1, X2)) -> prod(activate(X1), activate(X2))
activate(nfact(X)) -> fact(activate(X))
activate(np(X)) -> p(activate(X))
activate(X) -> X
On this DP problem, an Instantiation SCC transformation can be performed.
As a result of transforming the rule
IF(true, X, Y) -> ACTIVATE(X)
one new Dependency Pair
is created:
IF(true, ns(n0), nprod(X'0, nfact(np(X''')))) -> ACTIVATE(ns(n0))
The transformation is resulting in one new DP problem:
R
↳DPs
→DP Problem 1
↳SCP
→DP Problem 2
↳SCP
→DP Problem 3
↳Inst
→DP Problem 4
↳Instantiation Transformation
Dependency Pairs:
ACTIVATE(np(X)) -> ACTIVATE(X)
ACTIVATE(nfact(X)) -> ACTIVATE(X)
IF(true, ns(n0), nprod(X'0, nfact(np(X''')))) -> ACTIVATE(ns(n0))
FACT(X) -> IF(zero(X), ns(n0), nprod(X, nfact(np(X))))
ACTIVATE(nfact(X)) -> FACT(activate(X))
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X2)
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X1)
ACTIVATE(ns(X)) -> ACTIVATE(X)
IF(false, X, Y) -> ACTIVATE(Y)
Rules:
fact(X) -> if(zero(X), ns(n0), nprod(X, nfact(np(X))))
fact(X) -> nfact(X)
add(0, X) -> X
add(s(X), Y) -> s(add(X, Y))
prod(0, X) -> 0
prod(s(X), Y) -> add(Y, prod(X, Y))
prod(X1, X2) -> nprod(X1, X2)
if(true, X, Y) -> activate(X)
if(false, X, Y) -> activate(Y)
zero(0) -> true
zero(s(X)) -> false
p(s(X)) -> X
p(X) -> np(X)
s(X) -> ns(X)
0 -> n0
activate(ns(X)) -> s(activate(X))
activate(n0) -> 0
activate(nprod(X1, X2)) -> prod(activate(X1), activate(X2))
activate(nfact(X)) -> fact(activate(X))
activate(np(X)) -> p(activate(X))
activate(X) -> X
On this DP problem, an Instantiation SCC transformation can be performed.
As a result of transforming the rule
IF(false, X, Y) -> ACTIVATE(Y)
one new Dependency Pair
is created:
IF(false, ns(n0), nprod(X'0, nfact(np(X''')))) -> ACTIVATE(nprod(X'0, nfact(np(X'''))))
The transformation is resulting in one new DP problem:
R
↳DPs
→DP Problem 1
↳SCP
→DP Problem 2
↳SCP
→DP Problem 3
↳Inst
→DP Problem 4
↳Inst
...
→DP Problem 5
↳Remaining Obligation(s)
The following remains to be proven:
Dependency Pairs:
ACTIVATE(nfact(X)) -> ACTIVATE(X)
IF(false, ns(n0), nprod(X'0, nfact(np(X''')))) -> ACTIVATE(nprod(X'0, nfact(np(X'''))))
IF(true, ns(n0), nprod(X'0, nfact(np(X''')))) -> ACTIVATE(ns(n0))
FACT(X) -> IF(zero(X), ns(n0), nprod(X, nfact(np(X))))
ACTIVATE(nfact(X)) -> FACT(activate(X))
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X2)
ACTIVATE(nprod(X1, X2)) -> ACTIVATE(X1)
ACTIVATE(ns(X)) -> ACTIVATE(X)
ACTIVATE(np(X)) -> ACTIVATE(X)
Rules:
fact(X) -> if(zero(X), ns(n0), nprod(X, nfact(np(X))))
fact(X) -> nfact(X)
add(0, X) -> X
add(s(X), Y) -> s(add(X, Y))
prod(0, X) -> 0
prod(s(X), Y) -> add(Y, prod(X, Y))
prod(X1, X2) -> nprod(X1, X2)
if(true, X, Y) -> activate(X)
if(false, X, Y) -> activate(Y)
zero(0) -> true
zero(s(X)) -> false
p(s(X)) -> X
p(X) -> np(X)
s(X) -> ns(X)
0 -> n0
activate(ns(X)) -> s(activate(X))
activate(n0) -> 0
activate(nprod(X1, X2)) -> prod(activate(X1), activate(X2))
activate(nfact(X)) -> fact(activate(X))
activate(np(X)) -> p(activate(X))
activate(X) -> X
The Proof could not be continued due to a Timeout.
Termination of R could not be shown.
Duration:
1:00 minutes