Term Rewriting System R:
[X]
f(0) -> cons(0, nf(s(0)))
f(s(0)) -> f(p(s(0)))
f(X) -> nf(X)
p(s(0)) -> 0
activate(nf(X)) -> f(X)
activate(X) -> X
Termination of R to be shown.
R
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
f(0) -> cons(0, nf(s(0)))
f(X) -> nf(X)
activate(X) -> X
where the Polynomial interpretation:
POL(n__f(x1)) | = x1 |
POL(activate(x1)) | = 1 + x1 |
POL(0) | = 0 |
POL(cons(x1, x2)) | = x1 + x2 |
POL(s(x1)) | = x1 |
POL(f(x1)) | = 1 + x1 |
POL(p(x1)) | = x1 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
p(s(0)) -> 0
where the Polynomial interpretation:
POL(activate(x1)) | = x1 |
POL(n__f(x1)) | = x1 |
POL(0) | = 1 |
POL(s(x1)) | = 2·x1 |
POL(f(x1)) | = x1 |
POL(p(x1)) | = x1 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
activate(nf(X)) -> f(X)
where the Polynomial interpretation:
POL(activate(x1)) | = 1 + x1 |
POL(n__f(x1)) | = x1 |
POL(0) | = 0 |
POL(s(x1)) | = x1 |
POL(f(x1)) | = x1 |
POL(p(x1)) | = x1 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS4
↳Overlay and local confluence Check
The TRS is overlay and locally confluent (all critical pairs are trivially joinable).Hence, we can switch to innermost.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS5
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
F(s(0)) -> F(p(s(0)))
R contains no SCCs.
Termination of R successfully shown.
Duration:
0:00 minutes