Term Rewriting System R:
[Z, Y, X]
fst(0, Z) -> nil
fst(s, cons(Y)) -> cons(Y)
from(X) -> cons(X)
add(0, X) -> X
add(s, Y) -> s
len(nil) -> 0
len(cons(X)) -> s
Termination of R to be shown.
R
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
fst(0, Z) -> nil
add(0, X) -> X
len(cons(X)) -> s
where the Polynomial interpretation:
POL(from(x1)) | = x1 |
POL(0) | = 1 |
POL(cons(x1)) | = x1 |
POL(len(x1)) | = 1 + x1 |
POL(nil) | = 0 |
POL(fst(x1, x2)) | = x1 + x2 |
POL(s) | = 0 |
POL(add(x1, x2)) | = x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
len(nil) -> 0
where the Polynomial interpretation:
POL(from(x1)) | = x1 |
POL(0) | = 0 |
POL(cons(x1)) | = x1 |
POL(len(x1)) | = 1 + x1 |
POL(nil) | = 0 |
POL(s) | = 0 |
POL(fst(x1, x2)) | = x1 + x2 |
POL(add(x1, x2)) | = x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
add(s, Y) -> s
where the Polynomial interpretation:
POL(from(x1)) | = x1 |
POL(cons(x1)) | = x1 |
POL(fst(x1, x2)) | = x1 + x2 |
POL(s) | = 0 |
POL(add(x1, x2)) | = 1 + x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS4
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
fst(s, cons(Y)) -> cons(Y)
where the Polynomial interpretation:
POL(from(x1)) | = x1 |
POL(cons(x1)) | = x1 |
POL(fst(x1, x2)) | = 1 + x1 + x2 |
POL(s) | = 0 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS5
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
from(X) -> cons(X)
where the Polynomial interpretation:
POL(from(x1)) | = 1 + x1 |
POL(cons(x1)) | = x1 |
was used.
All Rules of R can be deleted.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS6
↳Overlay and local confluence Check
The TRS is overlay and locally confluent (all critical pairs are trivially joinable).Hence, we can switch to innermost.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS7
↳Dependency Pair Analysis
R contains no Dependency Pairs and therefore no SCCs.
Termination of R successfully shown.
Duration:
0:00 minutes