f(0) -> s(0)

f(s(0)) -> s(s(0))

f(s(0)) -> *(s(s(0)), f(0))

f(+(

f(+(

R

↳Dependency Pair Analysis

F(s(0)) -> F(0)

F(+(x, s(0))) -> F(x)

F(+(x,y)) -> F(x)

F(+(x,y)) -> F(y)

Furthermore,

R

↳DPs

→DP Problem 1

↳Remaining Obligation(s)

The following remains to be proven:

**F(+( x, y)) -> F(y)**

f(0) -> s(0)

f(s(0)) -> s(s(0))

f(s(0)) -> *(s(s(0)), f(0))

f(+(x, s(0))) -> +(s(s(0)), f(x))

f(+(x,y)) -> *(f(x), f(y))

Duration:

0:00 minutes