Term Rewriting System R:
[y, x]
+(0, y) -> y
+(s(x), 0) -> s(x)
+(s(x), s(y)) -> s(+(s(x), +(y, 0)))
Termination of R to be shown.
   R
     ↳Dependency Pair Analysis
R contains the following Dependency Pairs: 
+'(s(x), s(y)) -> +'(s(x), +(y, 0))
+'(s(x), s(y)) -> +'(y, 0)
Furthermore, R contains one SCC.
   R
     ↳DPs
       →DP Problem 1
         ↳Polynomial Ordering
Dependency Pair:
+'(s(x), s(y)) -> +'(s(x), +(y, 0))
Rules:
+(0, y) -> y
+(s(x), 0) -> s(x)
+(s(x), s(y)) -> s(+(s(x), +(y, 0)))
The following dependency pair can be strictly oriented:
+'(s(x), s(y)) -> +'(s(x), +(y, 0))
Additionally, the following usable rules w.r.t. to the implicit AFS can be oriented: 
+(0, y) -> y
+(s(x), 0) -> s(x)
+(s(x), s(y)) -> s(+(s(x), +(y, 0)))
Used ordering: Polynomial ordering with Polynomial interpretation:
| POL(0) | =  0 | 
| POL(s(x1)) | =  1 + x1 | 
| POL(+(x1, x2)) | =  x1 + x2 | 
| POL(+'(x1, x2)) | =  1 + x1 + x2 | 
 resulting in one new DP problem.
   R
     ↳DPs
       →DP Problem 1
         ↳Polo
           →DP Problem 2
             ↳Dependency Graph
Dependency Pair:
Rules:
+(0, y) -> y
+(s(x), 0) -> s(x)
+(s(x), s(y)) -> s(+(s(x), +(y, 0)))
Using the Dependency Graph resulted in no new DP problems.
Termination of R successfully shown.
Duration: 
0:00 minutes