R
↳Dependency Pair Analysis
*'(x, +(y, z)) -> *'(x, y)
*'(x, +(y, z)) -> *'(x, z)
*'(+(x, y), z) -> *'(x, z)
*'(+(x, y), z) -> *'(y, z)
R
↳DPs
→DP Problem 1
↳Polynomial Ordering
*'(+(x, y), z) -> *'(y, z)
*'(+(x, y), z) -> *'(x, z)
*'(x, +(y, z)) -> *'(x, z)
*'(x, +(y, z)) -> *'(x, y)
*(x, +(y, z)) -> +(*(x, y), *(x, z))
*(+(x, y), z) -> +(*(x, z), *(y, z))
*(x, 1) -> x
*(1, y) -> y
*'(+(x, y), z) -> *'(y, z)
*'(+(x, y), z) -> *'(x, z)
POL(*'(x1, x2)) = x1 POL(+(x1, x2)) = 1 + x1 + x2
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Polynomial Ordering
*'(x, +(y, z)) -> *'(x, z)
*'(x, +(y, z)) -> *'(x, y)
*(x, +(y, z)) -> +(*(x, y), *(x, z))
*(+(x, y), z) -> +(*(x, z), *(y, z))
*(x, 1) -> x
*(1, y) -> y
*'(x, +(y, z)) -> *'(x, z)
*'(x, +(y, z)) -> *'(x, y)
POL(*'(x1, x2)) = x2 POL(+(x1, x2)) = 1 + x1 + x2
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Polo
...
→DP Problem 3
↳Dependency Graph
*(x, +(y, z)) -> +(*(x, y), *(x, z))
*(+(x, y), z) -> +(*(x, z), *(y, z))
*(x, 1) -> x
*(1, y) -> y