Termination Proof using AProVE

Term Rewriting System R:
[x, y]
sum(0) -> 0
sum(s(x)) -> +(sum(x), s(x))
+(x, 0) -> x
+(x, s(y)) -> s(+(x, y))

Termination of R to be shown.

     ↳Dependency Pair Analysis

R contains the following Dependency Pairs:

SUM(s(x)) -> +'(sum(x), s(x))
SUM(s(x)) -> SUM(x)
+'(x, s(y)) -> +'(x, y)

Furthermore, R contains two SCCs.

     ↳DPs

       →DP Problem 1

         ↳Remaining Obligation(s)

       →DP Problem 2

         ↳Remaining Obligation(s)

The following remains to be proven:

Dependency Pair:
+'(x, s(y)) -> +'(x, y)

Rules:

sum(0) -> 0
sum(s(x)) -> +(sum(x), s(x))
+(x, 0) -> x
+(x, s(y)) -> s(+(x, y))
Dependency Pair:
SUM(s(x)) -> SUM(x)

Rules:

sum(0) -> 0
sum(s(x)) -> +(sum(x), s(x))
+(x, 0) -> x
+(x, s(y)) -> s(+(x, y))

     ↳DPs

       →DP Problem 1

         ↳Remaining Obligation(s)

       →DP Problem 2

         ↳Remaining Obligation(s)

The following remains to be proven:

Dependency Pair:
+'(x, s(y)) -> +'(x, y)

Rules:

sum(0) -> 0
sum(s(x)) -> +(sum(x), s(x))
+(x, 0) -> x
+(x, s(y)) -> s(+(x, y))
Dependency Pair:
SUM(s(x)) -> SUM(x)

Rules:

sum(0) -> 0
sum(s(x)) -> +(sum(x), s(x))
+(x, 0) -> x
+(x, s(y)) -> s(+(x, y))

Termination of R could not be shown.
Duration:
0:00 minutes