minus(0) -> 0

minus(minus(

+(

+(0,

+(minus(1), 1) -> 0

+(

+(

+(minus(+(

R

↳Dependency Pair Analysis

+'(x, minus(y)) -> MINUS(+(minus(x),y))

+'(x, minus(y)) -> +'(minus(x),y)

+'(x, minus(y)) -> MINUS(x)

+'(x, +(y,z)) -> +'(+(x,y),z)

+'(x, +(y,z)) -> +'(x,y)

+'(minus(+(x, 1)), 1) -> MINUS(x)

Furthermore,

R

↳DPs

→DP Problem 1

↳Remaining Obligation(s)

The following remains to be proven:

**+'( x, +(y, z)) -> +'(x, y)**

minus(0) -> 0

minus(minus(x)) ->x

+(x, 0) ->x

+(0,y) ->y

+(minus(1), 1) -> 0

+(x, minus(y)) -> minus(+(minus(x),y))

+(x, +(y,z)) -> +(+(x,y),z)

+(minus(+(x, 1)), 1) -> minus(x)

Duration:

0:00 minutes