Term Rewriting System R:
[y, x, z]
f(0, y) -> y
f(x, 0) -> x
f(i(x), y) -> i(x)
f(f(x, y), z) -> f(x, f(y, z))
f(g(x, y), z) -> g(f(x, z), f(y, z))
f(1, g(x, y)) -> x
f(2, g(x, y)) -> y

Termination of R to be shown. 



   R
     ↳Dependency Pair Analysis



R contains the following Dependency Pairs:

F(f(x, y), z) -> F(x, f(y, z))
F(f(x, y), z) -> F(y, z)
F(g(x, y), z) -> F(x, z)
F(g(x, y), z) -> F(y, z)

Furthermore, R contains one SCC. 


   R
     ↳DPs
       →DP Problem 1
         ↳Polynomial Ordering


Dependency Pairs:

F(g(x, y), z) -> F(y, z)
F(g(x, y), z) -> F(x, z)
F(f(x, y), z) -> F(y, z)
F(f(x, y), z) -> F(x, f(y, z))


Rules:


f(0, y) -> y
f(x, 0) -> x
f(i(x), y) -> i(x)
f(f(x, y), z) -> f(x, f(y, z))
f(g(x, y), z) -> g(f(x, z), f(y, z))
f(1, g(x, y)) -> x
f(2, g(x, y)) -> y





The following dependency pairs can be strictly oriented:

F(g(x, y), z) -> F(y, z)
F(g(x, y), z) -> F(x, z)


There are no usable rules w.r.t. to the implicit AFS that need to be oriented.

Used ordering: Polynomial ordering with Polynomial interpretation:
  POL(0)=  0  
  POL(i(x1))=  0  
  POL(g(x1, x2))=  1 + x1 + x2  
  POL(1)=  0  
  POL(2)=  0  
  POL(f(x1, x2))=  x1 + x2  
  POL(F(x1, x2))=  x1  

resulting in one new DP problem. 



   R
     ↳DPs
       →DP Problem 1
         ↳Polo
           →DP Problem 2
             ↳Polynomial Ordering


Dependency Pairs:

F(f(x, y), z) -> F(y, z)
F(f(x, y), z) -> F(x, f(y, z))


Rules:


f(0, y) -> y
f(x, 0) -> x
f(i(x), y) -> i(x)
f(f(x, y), z) -> f(x, f(y, z))
f(g(x, y), z) -> g(f(x, z), f(y, z))
f(1, g(x, y)) -> x
f(2, g(x, y)) -> y





The following dependency pairs can be strictly oriented:

F(f(x, y), z) -> F(y, z)
F(f(x, y), z) -> F(x, f(y, z))


There are no usable rules w.r.t. to the implicit AFS that need to be oriented.

Used ordering: Polynomial ordering with Polynomial interpretation:
  POL(0)=  0  
  POL(i(x1))=  0  
  POL(g(x1, x2))=  0  
  POL(1)=  0  
  POL(2)=  0  
  POL(f(x1, x2))=  1 + x1 + x2  
  POL(F(x1, x2))=  1 + x1  

resulting in one new DP problem. 



   R
     ↳DPs
       →DP Problem 1
         ↳Polo
           →DP Problem 2
             ↳Polo
             ...
               →DP Problem 3
                 ↳Dependency Graph


Dependency Pair:


Rules:


f(0, y) -> y
f(x, 0) -> x
f(i(x), y) -> i(x)
f(f(x, y), z) -> f(x, f(y, z))
f(g(x, y), z) -> g(f(x, z), f(y, z))
f(1, g(x, y)) -> x
f(2, g(x, y)) -> y





Using the Dependency Graph resulted in no new DP problems.

Termination of R successfully shown.
Duration:
0:00 minutes