R
↳Dependency Pair Analysis
+'(+(x, y), z) -> +'(x, +(y, z))
+'(+(x, y), z) -> +'(y, z)
+'(f(x), f(y)) -> +'(x, y)
+'(f(x), +(f(y), z)) -> +'(f(+(x, y)), z)
+'(f(x), +(f(y), z)) -> +'(x, y)
R
↳DPs
→DP Problem 1
↳Argument Filtering and Ordering
+'(f(x), +(f(y), z)) -> +'(x, y)
+'(f(x), +(f(y), z)) -> +'(f(+(x, y)), z)
+'(f(x), f(y)) -> +'(x, y)
+'(+(x, y), z) -> +'(y, z)
+'(+(x, y), z) -> +'(x, +(y, z))
+(+(x, y), z) -> +(x, +(y, z))
+(f(x), f(y)) -> f(+(x, y))
+(f(x), +(f(y), z)) -> +(f(+(x, y)), z)
+'(f(x), +(f(y), z)) -> +'(x, y)
+'(f(x), +(f(y), z)) -> +'(f(+(x, y)), z)
+'(f(x), f(y)) -> +'(x, y)
+(+(x, y), z) -> +(x, +(y, z))
+(f(x), f(y)) -> f(+(x, y))
+(f(x), +(f(y), z)) -> +(f(+(x, y)), z)
POL(+(x1, x2)) = x1 + x2 POL(f(x1)) = 1 + x1 POL(+'(x1, x2)) = 1 + x1 + x2
+'(x1, x2) -> +'(x1, x2)
+(x1, x2) -> +(x1, x2)
f(x1) -> f(x1)
R
↳DPs
→DP Problem 1
↳AFS
→DP Problem 2
↳Argument Filtering and Ordering
+'(+(x, y), z) -> +'(y, z)
+'(+(x, y), z) -> +'(x, +(y, z))
+(+(x, y), z) -> +(x, +(y, z))
+(f(x), f(y)) -> f(+(x, y))
+(f(x), +(f(y), z)) -> +(f(+(x, y)), z)
+'(+(x, y), z) -> +'(y, z)
+(+(x, y), z) -> +(x, +(y, z))
+(f(x), f(y)) -> f(+(x, y))
+(f(x), +(f(y), z)) -> +(f(+(x, y)), z)
POL(+(x1, x2)) = 1 + x1 + x2 POL(f(x1)) = x1 POL(+'(x1, x2)) = 1 + x1 + x2
+'(x1, x2) -> +'(x1, x2)
+(x1, x2) -> +(x1, x2)
f(x1) -> f(x1)
R
↳DPs
→DP Problem 1
↳AFS
→DP Problem 2
↳AFS
...
→DP Problem 3
↳Argument Filtering and Ordering
+'(+(x, y), z) -> +'(x, +(y, z))
+(+(x, y), z) -> +(x, +(y, z))
+(f(x), f(y)) -> f(+(x, y))
+(f(x), +(f(y), z)) -> +(f(+(x, y)), z)
+'(+(x, y), z) -> +'(x, +(y, z))
POL(+(x1, x2)) = 1 + x1 + x2
+'(x1, x2) -> x1
+(x1, x2) -> +(x1, x2)
R
↳DPs
→DP Problem 1
↳AFS
→DP Problem 2
↳AFS
...
→DP Problem 4
↳Dependency Graph
+(+(x, y), z) -> +(x, +(y, z))
+(f(x), f(y)) -> f(+(x, y))
+(f(x), +(f(y), z)) -> +(f(+(x, y)), z)