R
↳Dependency Pair Analysis
F(c(X, s(Y))) -> F(c(s(X), Y))
G(c(s(X), Y)) -> F(c(X, s(Y)))
R
↳DPs
→DP Problem 1
↳Instantiation Transformation
F(c(X, s(Y))) -> F(c(s(X), Y))
f(c(X, s(Y))) -> f(c(s(X), Y))
g(c(s(X), Y)) -> f(c(X, s(Y)))
one new Dependency Pair is created:
F(c(X, s(Y))) -> F(c(s(X), Y))
F(c(s(X''), s(Y''))) -> F(c(s(s(X'')), Y''))
R
↳DPs
→DP Problem 1
↳Inst
→DP Problem 2
↳Instantiation Transformation
F(c(s(X''), s(Y''))) -> F(c(s(s(X'')), Y''))
f(c(X, s(Y))) -> f(c(s(X), Y))
g(c(s(X), Y)) -> f(c(X, s(Y)))
one new Dependency Pair is created:
F(c(s(X''), s(Y''))) -> F(c(s(s(X'')), Y''))
F(c(s(s(X'''')), s(Y''''))) -> F(c(s(s(s(X''''))), Y''''))
R
↳DPs
→DP Problem 1
↳Inst
→DP Problem 2
↳Inst
...
→DP Problem 3
↳Polynomial Ordering
F(c(s(s(X'''')), s(Y''''))) -> F(c(s(s(s(X''''))), Y''''))
f(c(X, s(Y))) -> f(c(s(X), Y))
g(c(s(X), Y)) -> f(c(X, s(Y)))
F(c(s(s(X'''')), s(Y''''))) -> F(c(s(s(s(X''''))), Y''''))
POL(c(x1, x2)) = x2 POL(s(x1)) = 1 + x1 POL(F(x1)) = 1 + x1
R
↳DPs
→DP Problem 1
↳Inst
→DP Problem 2
↳Inst
...
→DP Problem 4
↳Dependency Graph
f(c(X, s(Y))) -> f(c(s(X), Y))
g(c(s(X), Y)) -> f(c(X, s(Y)))