R
↳Dependency Pair Analysis
APPEND(l1, l2) -> IFAPPEND(l1, l2, l1)
IFAPPEND(l1, l2, cons(x, l)) -> APPEND(l, l2)
R
↳DPs
→DP Problem 1
↳Polynomial Ordering
IFAPPEND(l1, l2, cons(x, l)) -> APPEND(l, l2)
APPEND(l1, l2) -> IFAPPEND(l1, l2, l1)
isempty(nil) -> true
isempty(cons(x, l)) -> false
hd(cons(x, l)) -> x
tl(cons(x, l)) -> l
append(l1, l2) -> ifappend(l1, l2, l1)
ifappend(l1, l2, nil) -> l2
ifappend(l1, l2, cons(x, l)) -> cons(x, append(l, l2))
IFAPPEND(l1, l2, cons(x, l)) -> APPEND(l, l2)
isempty(nil) -> true
isempty(cons(x, l)) -> false
hd(cons(x, l)) -> x
tl(cons(x, l)) -> l
append(l1, l2) -> ifappend(l1, l2, l1)
ifappend(l1, l2, nil) -> l2
ifappend(l1, l2, cons(x, l)) -> cons(x, append(l, l2))
POL(IFAPPEND(x1, x2, x3)) = x3 POL(cons(x1, x2)) = 1 + x1 + x2 POL(false) = 0 POL(ifappend(x1, x2, x3)) = x2 + x3 POL(hd(x1)) = x1 POL(nil) = 0 POL(true) = 0 POL(append(x1, x2)) = x1 + x2 POL(tl(x1)) = x1 POL(APPEND(x1, x2)) = x1 POL(is_empty(x1)) = 0
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Dependency Graph
APPEND(l1, l2) -> IFAPPEND(l1, l2, l1)
isempty(nil) -> true
isempty(cons(x, l)) -> false
hd(cons(x, l)) -> x
tl(cons(x, l)) -> l
append(l1, l2) -> ifappend(l1, l2, l1)
ifappend(l1, l2, nil) -> l2
ifappend(l1, l2, cons(x, l)) -> cons(x, append(l, l2))