Term Rewriting System R:
[x, y, z]
g(x, y) -> x
g(x, y) -> y
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))

Termination of R to be shown.



   R
Dependency Pair Analysis



R contains the following Dependency Pairs:

F(0, 1, x) -> F(s(x), x, x)
F(x, y, s(z)) -> F(0, 1, z)

Furthermore, R contains one SCC.


   R
DPs
       →DP Problem 1
Instantiation Transformation


Dependency Pairs:

F(x, y, s(z)) -> F(0, 1, z)
F(0, 1, x) -> F(s(x), x, x)


Rules:


g(x, y) -> x
g(x, y) -> y
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))





On this DP problem, an Instantiation SCC transformation can be performed.
As a result of transforming the rule

F(x, y, s(z)) -> F(0, 1, z)
two new Dependency Pairs are created:

F(0, 1, s(z'')) -> F(0, 1, z'')
F(s(x'''), y', s(z')) -> F(0, 1, z')

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Inst
           →DP Problem 2
Polynomial Ordering


Dependency Pairs:

F(0, 1, s(z'')) -> F(0, 1, z'')
F(s(x'''), y', s(z')) -> F(0, 1, z')
F(0, 1, x) -> F(s(x), x, x)


Rules:


g(x, y) -> x
g(x, y) -> y
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))





The following dependency pairs can be strictly oriented:

F(0, 1, s(z'')) -> F(0, 1, z'')
F(s(x'''), y', s(z')) -> F(0, 1, z')


There are no usable rules w.r.t. to the implicit AFS that need to be oriented.

Used ordering: Polynomial ordering with Polynomial interpretation:
  POL(0)=  0  
  POL(1)=  0  
  POL(s(x1))=  1 + x1  
  POL(F(x1, x2, x3))=  x3  

resulting in one new DP problem.



   R
DPs
       →DP Problem 1
Inst
           →DP Problem 2
Polo
             ...
               →DP Problem 3
Dependency Graph


Dependency Pair:

F(0, 1, x) -> F(s(x), x, x)


Rules:


g(x, y) -> x
g(x, y) -> y
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))





Using the Dependency Graph resulted in no new DP problems.

Termination of R successfully shown.
Duration:
0:00 minutes