Term Rewriting System R:
[x, y, z]
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))
Termination of R to be shown.
R
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
F(0, 1, x) -> F(s(x), x, x)
F(x, y, s(z)) -> F(0, 1, z)
Furthermore, R contains one SCC.
R
↳DPs
→DP Problem 1
↳Polynomial Ordering
Dependency Pairs:
F(x, y, s(z)) -> F(0, 1, z)
F(0, 1, x) -> F(s(x), x, x)
Rules:
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))
The following dependency pair can be strictly oriented:
F(x, y, s(z)) -> F(0, 1, z)
There are no usable rules w.r.t. to the implicit AFS that need to be oriented.
Used ordering: Polynomial ordering with Polynomial interpretation:
POL(0) | = 0 |
POL(1) | = 0 |
POL(s(x1)) | = 1 + x1 |
POL(F(x1, x2, x3)) | = x3 |
resulting in one new DP problem.
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Dependency Graph
Dependency Pair:
F(0, 1, x) -> F(s(x), x, x)
Rules:
f(0, 1, x) -> f(s(x), x, x)
f(x, y, s(z)) -> s(f(0, 1, z))
Using the Dependency Graph resulted in no new DP problems.
Termination of R successfully shown.
Duration:
0:00 minutes