Term Rewriting System R:
[x]
f(s(x)) -> s(s(f(p(s(x)))))
f(0) -> 0
p(s(x)) -> x
Innermost Termination of R to be shown.
R
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
F(s(x)) -> F(p(s(x)))
F(s(x)) -> P(s(x))
Furthermore, R contains one SCC.
R
↳DPs
→DP Problem 1
↳Rewriting Transformation
Dependency Pair:
F(s(x)) -> F(p(s(x)))
Rules:
f(s(x)) -> s(s(f(p(s(x)))))
f(0) -> 0
p(s(x)) -> x
Strategy:
innermost
On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule
F(s(x)) -> F(p(s(x)))
one new Dependency Pair
is created:
F(s(x)) -> F(x)
The transformation is resulting in one new DP problem:
R
↳DPs
→DP Problem 1
↳Rw
→DP Problem 2
↳Forward Instantiation Transformation
Dependency Pair:
F(s(x)) -> F(x)
Rules:
f(s(x)) -> s(s(f(p(s(x)))))
f(0) -> 0
p(s(x)) -> x
Strategy:
innermost
On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule
F(s(x)) -> F(x)
one new Dependency Pair
is created:
F(s(s(x''))) -> F(s(x''))
The transformation is resulting in one new DP problem:
R
↳DPs
→DP Problem 1
↳Rw
→DP Problem 2
↳FwdInst
...
→DP Problem 3
↳Argument Filtering and Ordering
Dependency Pair:
F(s(s(x''))) -> F(s(x''))
Rules:
f(s(x)) -> s(s(f(p(s(x)))))
f(0) -> 0
p(s(x)) -> x
Strategy:
innermost
The following dependency pair can be strictly oriented:
F(s(s(x''))) -> F(s(x''))
There are no usable rules for innermost that need to be oriented.
Used ordering: Polynomial ordering with Polynomial interpretation:
| POL(s(x1)) | = 1 + x1 |
| POL(F(x1)) | = 1 + x1 |
resulting in one new DP problem.
Used Argument Filtering System: F(x1) -> F(x1)
s(x1) -> s(x1)
R
↳DPs
→DP Problem 1
↳Rw
→DP Problem 2
↳FwdInst
...
→DP Problem 4
↳Dependency Graph
Dependency Pair:
Rules:
f(s(x)) -> s(s(f(p(s(x)))))
f(0) -> 0
p(s(x)) -> x
Strategy:
innermost
Using the Dependency Graph resulted in no new DP problems.
Innermost Termination of R successfully shown.
Duration:
0:00 minutes