Term Rewriting System R:
[x, y]
-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))

Innermost Termination of R to be shown.



   R
Dependency Pair Analysis



R contains the following Dependency Pairs:

-'(s(x), s(y)) -> -'(x, y)
+'(s(x), y) -> +'(x, y)
*'(x, s(y)) -> +'(x, *(x, y))
*'(x, s(y)) -> *'(x, y)
F(s(x)) -> F(-(p(*(s(x), s(x))), *(s(x), s(x))))
F(s(x)) -> -'(p(*(s(x), s(x))), *(s(x), s(x)))
F(s(x)) -> P(*(s(x), s(x)))
F(s(x)) -> *'(s(x), s(x))

Furthermore, R contains four SCCs.


   R
DPs
       →DP Problem 1
Polynomial Ordering
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw


Dependency Pair:

-'(s(x), s(y)) -> -'(x, y)


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




The following dependency pair can be strictly oriented:

-'(s(x), s(y)) -> -'(x, y)


There are no usable rules for innermost that need to be oriented.

Used ordering: Polynomial ordering with Polynomial interpretation:
  POL(-'(x1, x2))=  x1  
  POL(s(x1))=  1 + x1  

resulting in one new DP problem.



   R
DPs
       →DP Problem 1
Polo
           →DP Problem 5
Dependency Graph
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw


Dependency Pair:


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polynomial Ordering
       →DP Problem 3
Polo
       →DP Problem 4
Rw


Dependency Pair:

+'(s(x), y) -> +'(x, y)


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




The following dependency pair can be strictly oriented:

+'(s(x), y) -> +'(x, y)


There are no usable rules for innermost that need to be oriented.

Used ordering: Polynomial ordering with Polynomial interpretation:
  POL(s(x1))=  1 + x1  
  POL(+'(x1, x2))=  x1  

resulting in one new DP problem.



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
           →DP Problem 6
Dependency Graph
       →DP Problem 3
Polo
       →DP Problem 4
Rw


Dependency Pair:


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polynomial Ordering
       →DP Problem 4
Rw


Dependency Pair:

*'(x, s(y)) -> *'(x, y)


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




The following dependency pair can be strictly oriented:

*'(x, s(y)) -> *'(x, y)


There are no usable rules for innermost that need to be oriented.

Used ordering: Polynomial ordering with Polynomial interpretation:
  POL(*'(x1, x2))=  x2  
  POL(s(x1))=  1 + x1  

resulting in one new DP problem.



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
           →DP Problem 7
Dependency Graph
       →DP Problem 4
Rw


Dependency Pair:


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rewriting Transformation


Dependency Pair:

F(s(x)) -> F(-(p(*(s(x), s(x))), *(s(x), s(x))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(x)) -> F(-(p(*(s(x), s(x))), *(s(x), s(x))))
one new Dependency Pair is created:

F(s(x)) -> F(-(p(+(s(x), *(s(x), x))), *(s(x), s(x))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rewriting Transformation


Dependency Pair:

F(s(x)) -> F(-(p(+(s(x), *(s(x), x))), *(s(x), s(x))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(x)) -> F(-(p(+(s(x), *(s(x), x))), *(s(x), s(x))))
one new Dependency Pair is created:

F(s(x)) -> F(-(p(s(+(x, *(s(x), x)))), *(s(x), s(x))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 9
Rewriting Transformation


Dependency Pair:

F(s(x)) -> F(-(p(s(+(x, *(s(x), x)))), *(s(x), s(x))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(x)) -> F(-(p(s(+(x, *(s(x), x)))), *(s(x), s(x))))
one new Dependency Pair is created:

F(s(x)) -> F(-(+(x, *(s(x), x)), *(s(x), s(x))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 10
Rewriting Transformation


Dependency Pair:

F(s(x)) -> F(-(+(x, *(s(x), x)), *(s(x), s(x))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(x)) -> F(-(+(x, *(s(x), x)), *(s(x), s(x))))
one new Dependency Pair is created:

F(s(x)) -> F(-(+(x, *(s(x), x)), +(s(x), *(s(x), x))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 11
Rewriting Transformation


Dependency Pair:

F(s(x)) -> F(-(+(x, *(s(x), x)), +(s(x), *(s(x), x))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(x)) -> F(-(+(x, *(s(x), x)), +(s(x), *(s(x), x))))
one new Dependency Pair is created:

F(s(x)) -> F(-(+(x, *(s(x), x)), s(+(x, *(s(x), x)))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 12
Narrowing Transformation


Dependency Pair:

F(s(x)) -> F(-(+(x, *(s(x), x)), s(+(x, *(s(x), x)))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

F(s(x)) -> F(-(+(x, *(s(x), x)), s(+(x, *(s(x), x)))))
eight new Dependency Pairs are created:

F(s(0)) -> F(-(*(s(0), 0), s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(+(s(x''), *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(+(0, 0), s(+(0, *(s(0), 0)))))
F(s(s(y'))) -> F(-(+(s(y'), +(s(s(y')), *(s(s(y')), y'))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 13
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(s(y'), +(s(s(y')), *(s(s(y')), y'))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(+(0, 0), s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(+(s(x''), *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, *(s(0), 0)))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(*(s(0), 0), s(+(0, *(s(0), 0)))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 14
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(s(y'), +(s(s(y')), *(s(s(y')), y'))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(+(0, 0), s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(+(s(x''), *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(+(s(x''), *(s(s(x'')), s(x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 15
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(s(y'), +(s(s(y')), *(s(s(y')), y'))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(+(0, 0), s(+(0, *(s(0), 0)))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(+(0, 0), s(+(0, *(s(0), 0)))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 16
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(s(y'), +(s(s(y')), *(s(s(y')), y'))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(s(y'), +(s(s(y')), *(s(s(y')), y'))), s(+(s(y'), *(s(s(y')), s(y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 17
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(+(0, *(s(0), 0)), s(*(s(0), 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 18
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(s(x''), *(s(s(x'')), s(x''))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 19
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(+(0, *(s(0), 0)), s(+(0, 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 20
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(s(y'), *(s(s(y')), s(y'))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 21
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(*(s(0), 0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 22
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), +(s(x''), *(s(s(x'')), s(x'')))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 23
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(+(0, *(s(0), 0)))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(*(s(0), 0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 24
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(s(+(y', +(s(s(y')), *(s(s(y')), y')))), s(+(s(y'), *(s(s(y')), s(y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 25
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(*(s(0), 0), s(*(s(0), 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(*(s(0), 0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 26
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(s(+(x'', *(s(s(x'')), s(x'')))), s(s(+(x'', *(s(s(x'')), s(x'')))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 27
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(*(s(0), 0), s(+(0, 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(+(0, 0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 28
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(s(+(y', *(s(s(y')), s(y')))), s(+(s(y'), +(s(s(y')), *(s(s(y')), y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 29
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(+(0, 0))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(*(s(0), 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(0)))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 30
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), +(s(x''), *(s(s(x'')), s(x'')))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 31
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(0)))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(*(s(0), 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(0)))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 32
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), *(s(s(y')), s(y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 33
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(*(s(0), 0))))
F(s(0)) -> F(-(0, s(0)))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(*(s(0), 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(0)))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 34
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', *(s(s(x'')), s(x''))), s(+(x'', *(s(s(x'')), s(x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 35
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(+(0, 0))))
F(s(0)) -> F(-(0, s(0)))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(+(0, 0))))
one new Dependency Pair is created:

F(s(0)) -> F(-(0, s(0)))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 36
Rewriting Transformation


Dependency Pairs:

F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', *(s(s(y')), s(y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 37
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), +(s(x''), *(s(s(x'')), s(x'')))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), +(s(x''), *(s(s(x'')), s(x'')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 38
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), *(s(s(y')), s(y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), *(s(s(y')), s(y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 39
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), *(s(s(y')), s(y')))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), +(s(x''), *(s(s(x'')), s(x'')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', +(s(s(x'')), *(s(s(x'')), x''))), s(+(x'', *(s(s(x'')), s(x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), s(+(x'', *(s(s(x'')), s(x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 40
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), *(s(s(y')), s(y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', +(s(s(y')), *(s(s(y')), y'))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 41
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), *(s(s(y')), s(y')))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), +(s(x''), *(s(s(x'')), s(x'')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), s(+(x'', *(s(s(x'')), s(x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), +(s(x''), *(s(s(x'')), s(x'')))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 42
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), *(s(s(y')), s(y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), *(s(s(y')), s(y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', *(s(s(y')), s(y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 43
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', *(s(s(y')), s(y'))))))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(+(s(x''), *(s(s(x'')), x'')))), s(+(x'', *(s(s(x'')), s(x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 44
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', *(s(s(y')), s(y'))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(+(s(y'), *(s(s(y')), y')))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 45
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', *(s(s(y')), s(y'))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 46
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', *(s(s(y')), s(y'))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', *(s(s(y')), s(y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 47
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', *(s(s(x'')), s(x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 48
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), +(s(y'), +(s(s(y')), *(s(s(y')), y')))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 49
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 50
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 51
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', +(s(s(x'')), *(s(s(x'')), x''))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 52
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', +(s(s(y')), *(s(s(y')), y'))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 53
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 54
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 55
Rewriting Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(+(s(x''), *(s(s(x'')), x'')))))))
one new Dependency Pair is created:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 56
Rewriting Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(+(s(y'), *(s(s(y')), y')))))))
one new Dependency Pair is created:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 57
Narrowing Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(0)))
no new Dependency Pairs are created.
The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 58
Narrowing Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(0)))
no new Dependency Pairs are created.
The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 59
Narrowing Transformation


Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(0)) -> F(-(0, s(0)))
F(s(0)) -> F(-(0, s(0)))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(0)))
no new Dependency Pairs are created.
The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 60
Narrowing Transformation


Dependency Pairs:

F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(0)) -> F(-(0, s(0)))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

F(s(0)) -> F(-(0, s(0)))
no new Dependency Pairs are created.
The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
Polo
       →DP Problem 2
Polo
       →DP Problem 3
Polo
       →DP Problem 4
Rw
           →DP Problem 8
Rw
             ...
               →DP Problem 61
Remaining Obligation(s)




The following remains to be proven:
Dependency Pairs:

F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(y'))) -> F(-(+(y', s(s(+(y', *(s(s(y')), y'))))), s(+(y', s(s(+(y', *(s(s(y')), y'))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))
F(s(s(x''))) -> F(-(+(x'', s(s(+(x'', *(s(s(x'')), x''))))), s(+(x'', s(s(+(x'', *(s(s(x'')), x''))))))))


Rules:


-(x, 0) -> x
-(s(x), s(y)) -> -(x, y)
+(0, y) -> y
+(s(x), y) -> s(+(x, y))
*(x, 0) -> 0
*(x, s(y)) -> +(x, *(x, y))
p(s(x)) -> x
f(s(x)) -> f(-(p(*(s(x), s(x))), *(s(x), s(x))))


Strategy:

innermost



Innermost Termination of R could not be shown.
Duration:
0:05 minutes