f(s(

g(0, 1) -> s(0)

0 -> 1

R

↳Removing Redundant Rules for Innermost Termination

Removing the following rules from

g(0, 1) -> s(0)

R

↳RRRI

→TRS2

↳Removing Redundant Rules

Removing the following rules from

f(s(x)) -> f(g(x,x))

where the Polynomial interpretation:

was used.

_{ }^{ }POL(0)= 0 _{ }^{ }_{ }^{ }POL(g(x)_{1}, x_{2})= x _{1}+ x_{2}_{ }^{ }_{ }^{ }POL(1)= 0 _{ }^{ }_{ }^{ }POL(s(x)_{1})= 1 + 2·x _{1}_{ }^{ }_{ }^{ }POL(f(x)_{1})= x _{1}_{ }^{ }

Not all Rules of

R

↳RRRI

→TRS2

↳RRRPolo

→TRS3

↳Removing Redundant Rules

Removing the following rules from

0 -> 1

where the Polynomial interpretation:

was used.

_{ }^{ }POL(0)= 1 _{ }^{ }_{ }^{ }POL(1)= 0 _{ }^{ }

All Rules of

R

↳RRRI

→TRS2

↳RRRPolo

→TRS3

↳RRRPolo

...

→TRS4

↳Dependency Pair Analysis

Duration:

0:00 minutes