Term Rewriting System R:
[y, x, f]
app(app(plus, 0), y) -> y
app(app(plus, app(s, x)), y) -> app(s, app(app(plus, x), y))
app(app(app(curry, f), x), y) -> app(app(f, x), y)
add -> app(curry, plus)

Innermost Termination of R to be shown.



   R
Dependency Pair Analysis



R contains the following Dependency Pairs:

APP(app(plus, app(s, x)), y) -> APP(s, app(app(plus, x), y))
APP(app(plus, app(s, x)), y) -> APP(app(plus, x), y)
APP(app(plus, app(s, x)), y) -> APP(plus, x)
APP(app(app(curry, f), x), y) -> APP(app(f, x), y)
APP(app(app(curry, f), x), y) -> APP(f, x)
ADD -> APP(curry, plus)

Furthermore, R contains one SCC.


   R
DPs
       →DP Problem 1
Forward Instantiation Transformation


Dependency Pairs:

APP(app(app(curry, f), x), y) -> APP(f, x)
APP(app(app(curry, f), x), y) -> APP(app(f, x), y)
APP(app(plus, app(s, x)), y) -> APP(app(plus, x), y)


Rules:


app(app(plus, 0), y) -> y
app(app(plus, app(s, x)), y) -> app(s, app(app(plus, x), y))
app(app(app(curry, f), x), y) -> app(app(f, x), y)
add -> app(curry, plus)


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

APP(app(app(curry, f), x), y) -> APP(f, x)
two new Dependency Pairs are created:

APP(app(app(curry, app(app(curry, f''), x'')), x0), y) -> APP(app(app(curry, f''), x''), x0)
APP(app(app(curry, app(plus, app(s, x''))), x0), y) -> APP(app(plus, app(s, x'')), x0)

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
           →DP Problem 2
Remaining Obligation(s)




The following remains to be proven:
Dependency Pairs:

APP(app(app(curry, app(plus, app(s, x''))), x0), y) -> APP(app(plus, app(s, x'')), x0)
APP(app(app(curry, app(app(curry, f''), x'')), x0), y) -> APP(app(app(curry, f''), x''), x0)
APP(app(plus, app(s, x)), y) -> APP(app(plus, x), y)
APP(app(app(curry, f), x), y) -> APP(app(f, x), y)


Rules:


app(app(plus, 0), y) -> y
app(app(plus, app(s, x)), y) -> app(s, app(app(plus, x), y))
app(app(app(curry, f), x), y) -> app(app(f, x), y)
add -> app(curry, plus)


Strategy:

innermost



Innermost Termination of R could not be shown.
Duration:
0:00 minutes