Term Rewriting System R:
[y, x]
-(0, y) -> 0
-(x, 0) -> x
-(x, s(y)) -> if(greater(x, s(y)), s(-(x, p(s(y)))), 0)
p(0) -> 0
p(s(x)) -> x

Innermost Termination of R to be shown.



   R
Dependency Pair Analysis



R contains the following Dependency Pairs:

-'(x, s(y)) -> -'(x, p(s(y)))
-'(x, s(y)) -> P(s(y))

Furthermore, R contains one SCC.


   R
DPs
       →DP Problem 1
Usable Rules (Innermost)


Dependency Pair:

-'(x, s(y)) -> -'(x, p(s(y)))


Rules:


-(0, y) -> 0
-(x, 0) -> x
-(x, s(y)) -> if(greater(x, s(y)), s(-(x, p(s(y)))), 0)
p(0) -> 0
p(s(x)) -> x


Strategy:

innermost




As we are in the innermost case, we can delete all 4 non-usable-rules.


   R
DPs
       →DP Problem 1
UsableRules
           →DP Problem 2
Rewriting Transformation


Dependency Pair:

-'(x, s(y)) -> -'(x, p(s(y)))


Rule:


p(s(x)) -> x


Strategy:

innermost




On this DP problem, a Rewriting SCC transformation can be performed.
As a result of transforming the rule

-'(x, s(y)) -> -'(x, p(s(y)))
one new Dependency Pair is created:

-'(x, s(y)) -> -'(x, y)

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
UsableRules
           →DP Problem 2
Rw
             ...
               →DP Problem 3
Usable Rules (Innermost)


Dependency Pair:

-'(x, s(y)) -> -'(x, y)


Rule:


p(s(x)) -> x


Strategy:

innermost




As we are in the innermost case, we can delete all 1 non-usable-rules.


   R
DPs
       →DP Problem 1
UsableRules
           →DP Problem 2
Rw
             ...
               →DP Problem 4
Size-Change Principle


Dependency Pair:

-'(x, s(y)) -> -'(x, y)


Rule:

none


Strategy:

innermost




We number the DPs as follows:
  1. -'(x, s(y)) -> -'(x, y)
and get the following Size-Change Graph(s):
{1} , {1}
1=1
2>2

which lead(s) to this/these maximal multigraph(s):
{1} , {1}
1=1
2>2

DP: empty set
Oriented Rules: none

We used the order Homeomorphic Embedding Order with Non-Strict Precedence.
trivial

with Argument Filtering System:
s(x1) -> s(x1)

We obtain no new DP problems.

Innermost Termination of R successfully shown.
Duration:
0:00 minutes