Term Rewriting System R:
[x, y, z]
f(+(x, 0)) -> f(x)
+(x, +(y, z)) -> +(+(x, y), z)
Innermost Termination of R to be shown.
R
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
F(+(x, 0)) -> F(x)
+'(x, +(y, z)) -> +'(+(x, y), z)
+'(x, +(y, z)) -> +'(x, y)
Furthermore, R contains two SCCs.
R
↳DPs
→DP Problem 1
↳Polynomial Ordering
→DP Problem 2
↳Polo
Dependency Pair:
F(+(x, 0)) -> F(x)
Rules:
f(+(x, 0)) -> f(x)
+(x, +(y, z)) -> +(+(x, y), z)
Strategy:
innermost
The following dependency pair can be strictly oriented:
F(+(x, 0)) -> F(x)
There are no usable rules for innermost w.r.t. to the implicit AFS that need to be oriented.
Used ordering: Polynomial ordering with Polynomial interpretation:
| POL(0) | = 0 |
| POL(F(x1)) | = x1 |
| POL(+(x1, x2)) | = 1 + x1 |
resulting in one new DP problem.
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 3
↳Dependency Graph
→DP Problem 2
↳Polo
Dependency Pair:
Rules:
f(+(x, 0)) -> f(x)
+(x, +(y, z)) -> +(+(x, y), z)
Strategy:
innermost
Using the Dependency Graph resulted in no new DP problems.
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Polynomial Ordering
Dependency Pair:
+'(x, +(y, z)) -> +'(x, y)
Rules:
f(+(x, 0)) -> f(x)
+(x, +(y, z)) -> +(+(x, y), z)
Strategy:
innermost
The following dependency pair can be strictly oriented:
+'(x, +(y, z)) -> +'(x, y)
There are no usable rules for innermost w.r.t. to the implicit AFS that need to be oriented.
Used ordering: Polynomial ordering with Polynomial interpretation:
| POL(+(x1, x2)) | = 1 + x1 |
| POL(+'(x1, x2)) | = x2 |
resulting in one new DP problem.
R
↳DPs
→DP Problem 1
↳Polo
→DP Problem 2
↳Polo
→DP Problem 4
↳Dependency Graph
Dependency Pair:
Rules:
f(+(x, 0)) -> f(x)
+(x, +(y, z)) -> +(+(x, y), z)
Strategy:
innermost
Using the Dependency Graph resulted in no new DP problems.
Innermost Termination of R successfully shown.
Duration:
0:00 minutes