Term Rewriting System R:
[x, y, z, t, a, b, c]
g(A) -> A
g(B) -> A
g(B) -> B
g(C) -> A
g(C) -> B
g(C) -> C
foldf(x, nil) -> x
foldf(x, cons(y, z)) -> f(foldf(x, z), y)
f(t, x) -> f'(t, g(x))
f'(triple(a, b, c), C) -> triple(a, b, cons(C, c))
f'(triple(a, b, c), B) -> f(triple(a, b, c), A)
f'(triple(a, b, c), A) -> f''(foldf(triple(cons(A, a), nil, c), b))
f''(triple(a, b, c)) -> foldf(triple(a, b, nil), c)
Innermost Termination of R to be shown.
R
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
g(B) -> A
g(C) -> A
f'(triple(a, b, c), B) -> f(triple(a, b, c), A)
where the Polynomial interpretation:
| POL(C) | = 1 |
| POL(g(x1)) | = x1 |
| POL(B) | = 1 |
| POL(cons(x1, x2)) | = x1 + x2 |
| POL(nil) | = 0 |
| POL(triple(x1, x2, x3)) | = x1 + x2 + x3 |
| POL(foldf(x1, x2)) | = x1 + x2 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(f''(x1)) | = x1 |
| POL(A) | = 0 |
| POL(f(x1, x2)) | = x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
f'(triple(a, b, c), A) -> f''(foldf(triple(cons(A, a), nil, c), b))
where the Polynomial interpretation:
| POL(C) | = 0 |
| POL(g(x1)) | = x1 |
| POL(B) | = 0 |
| POL(cons(x1, x2)) | = 1 + x1 + x2 |
| POL(triple(x1, x2, x3)) | = x1 + 2·x2 + 2·x3 |
| POL(nil) | = 0 |
| POL(f'(x1, x2)) | = 2 + x1 + x2 |
| POL(foldf(x1, x2)) | = x1 + 2·x2 |
| POL(f''(x1)) | = x1 |
| POL(A) | = 0 |
| POL(f(x1, x2)) | = 2 + x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
f'(triple(a, b, c), C) -> triple(a, b, cons(C, c))
where the Polynomial interpretation:
| POL(C) | = 0 |
| POL(g(x1)) | = x1 |
| POL(B) | = 0 |
| POL(cons(x1, x2)) | = 1 + x1 + x2 |
| POL(triple(x1, x2, x3)) | = x1 + x2 + x3 |
| POL(nil) | = 0 |
| POL(foldf(x1, x2)) | = x1 + 2·x2 |
| POL(f'(x1, x2)) | = 2 + x1 + x2 |
| POL(f''(x1)) | = 2·x1 |
| POL(A) | = 0 |
| POL(f(x1, x2)) | = 2 + x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS4
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
g(B) -> B
g(C) -> C
g(C) -> B
where the Polynomial interpretation:
| POL(C) | = 1 |
| POL(g(x1)) | = 2·x1 |
| POL(B) | = 1 |
| POL(cons(x1, x2)) | = 2·x1 + x2 |
| POL(triple(x1, x2, x3)) | = x1 + x2 + x3 |
| POL(nil) | = 0 |
| POL(foldf(x1, x2)) | = x1 + x2 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(f''(x1)) | = x1 |
| POL(A) | = 0 |
| POL(f(x1, x2)) | = x1 + 2·x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS5
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
f''(triple(a, b, c)) -> foldf(triple(a, b, nil), c)
where the Polynomial interpretation:
| POL(g(x1)) | = x1 |
| POL(cons(x1, x2)) | = x1 + x2 |
| POL(nil) | = 0 |
| POL(triple(x1, x2, x3)) | = x1 + x2 + x3 |
| POL(foldf(x1, x2)) | = x1 + x2 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(f''(x1)) | = 1 + x1 |
| POL(f(x1, x2)) | = x1 + x2 |
| POL(A) | = 0 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS6
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
foldf(x, cons(y, z)) -> f(foldf(x, z), y)
where the Polynomial interpretation:
| POL(g(x1)) | = x1 |
| POL(cons(x1, x2)) | = 1 + x1 + x2 |
| POL(nil) | = 0 |
| POL(foldf(x1, x2)) | = x1 + x2 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(f(x1, x2)) | = x1 + x2 |
| POL(A) | = 0 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS7
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
foldf(x, nil) -> x
where the Polynomial interpretation:
| POL(g(x1)) | = x1 |
| POL(nil) | = 0 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(foldf(x1, x2)) | = 1 + x1 + x2 |
| POL(A) | = 0 |
| POL(f(x1, x2)) | = x1 + x2 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS8
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
g(A) -> A
where the Polynomial interpretation:
| POL(g(x1)) | = 1 + x1 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(f(x1, x2)) | = 1 + x1 + x2 |
| POL(A) | = 0 |
was used.
Not all Rules of R can be deleted, so we still have to regard a part of R.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS9
↳Removing Redundant Rules
Removing the following rules from R which fullfill a polynomial ordering:
f(t, x) -> f'(t, g(x))
where the Polynomial interpretation:
| POL(g(x1)) | = x1 |
| POL(f'(x1, x2)) | = x1 + x2 |
| POL(f(x1, x2)) | = 1 + x1 + x2 |
was used.
All Rules of R can be deleted.
R
↳RRRPolo
→TRS2
↳RRRPolo
→TRS3
↳RRRPolo
...
→TRS10
↳Dependency Pair Analysis
R contains no Dependency Pairs and therefore no SCCs.
Innermost Termination of R successfully shown.
Duration:
0:01 minutes