Term Rewriting System R:
[y, x]
le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))

Innermost Termination of R to be shown.



   R
Dependency Pair Analysis



R contains the following Dependency Pairs:

LE(s(x), s(y)) -> LE(x, y)
MINUS(s(x), s(y)) -> MINUS(x, y)
GCD(s(x), s(y)) -> IFGCD(le(y, x), s(x), s(y))
GCD(s(x), s(y)) -> LE(y, x)
IFGCD(true, s(x), s(y)) -> GCD(minus(x, y), s(y))
IFGCD(true, s(x), s(y)) -> MINUS(x, y)
IFGCD(false, s(x), s(y)) -> GCD(minus(y, x), s(x))
IFGCD(false, s(x), s(y)) -> MINUS(y, x)

Furthermore, R contains three SCCs.


   R
DPs
       →DP Problem 1
Forward Instantiation Transformation
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar


Dependency Pair:

LE(s(x), s(y)) -> LE(x, y)


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

LE(s(x), s(y)) -> LE(x, y)
one new Dependency Pair is created:

LE(s(s(x'')), s(s(y''))) -> LE(s(x''), s(y''))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
           →DP Problem 4
Forward Instantiation Transformation
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar


Dependency Pair:

LE(s(s(x'')), s(s(y''))) -> LE(s(x''), s(y''))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

LE(s(s(x'')), s(s(y''))) -> LE(s(x''), s(y''))
one new Dependency Pair is created:

LE(s(s(s(x''''))), s(s(s(y'''')))) -> LE(s(s(x'''')), s(s(y'''')))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
           →DP Problem 4
FwdInst
             ...
               →DP Problem 5
Argument Filtering and Ordering
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar


Dependency Pair:

LE(s(s(s(x''''))), s(s(s(y'''')))) -> LE(s(s(x'''')), s(s(y'''')))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pair can be strictly oriented:

LE(s(s(s(x''''))), s(s(s(y'''')))) -> LE(s(s(x'''')), s(s(y'''')))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
trivial

resulting in one new DP problem.
Used Argument Filtering System:
LE(x1, x2) -> LE(x1, x2)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
           →DP Problem 4
FwdInst
             ...
               →DP Problem 6
Dependency Graph
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar


Dependency Pair:


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
Forward Instantiation Transformation
       →DP Problem 3
Nar


Dependency Pair:

MINUS(s(x), s(y)) -> MINUS(x, y)


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

MINUS(s(x), s(y)) -> MINUS(x, y)
one new Dependency Pair is created:

MINUS(s(s(x'')), s(s(y''))) -> MINUS(s(x''), s(y''))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
           →DP Problem 7
Forward Instantiation Transformation
       →DP Problem 3
Nar


Dependency Pair:

MINUS(s(s(x'')), s(s(y''))) -> MINUS(s(x''), s(y''))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

MINUS(s(s(x'')), s(s(y''))) -> MINUS(s(x''), s(y''))
one new Dependency Pair is created:

MINUS(s(s(s(x''''))), s(s(s(y'''')))) -> MINUS(s(s(x'''')), s(s(y'''')))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
           →DP Problem 7
FwdInst
             ...
               →DP Problem 8
Argument Filtering and Ordering
       →DP Problem 3
Nar


Dependency Pair:

MINUS(s(s(s(x''''))), s(s(s(y'''')))) -> MINUS(s(s(x'''')), s(s(y'''')))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pair can be strictly oriented:

MINUS(s(s(s(x''''))), s(s(s(y'''')))) -> MINUS(s(s(x'''')), s(s(y'''')))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
trivial

resulting in one new DP problem.
Used Argument Filtering System:
MINUS(x1, x2) -> MINUS(x1, x2)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
           →DP Problem 7
FwdInst
             ...
               →DP Problem 9
Dependency Graph
       →DP Problem 3
Nar


Dependency Pair:


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Narrowing Transformation


Dependency Pairs:

IFGCD(false, s(x), s(y)) -> GCD(minus(y, x), s(x))
IFGCD(true, s(x), s(y)) -> GCD(minus(x, y), s(y))
GCD(s(x), s(y)) -> IFGCD(le(y, x), s(x), s(y))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

GCD(s(x), s(y)) -> IFGCD(le(y, x), s(x), s(y))
three new Dependency Pairs are created:

GCD(s(x'), s(0)) -> IFGCD(true, s(x'), s(0))
GCD(s(0), s(s(x''))) -> IFGCD(false, s(0), s(s(x'')))
GCD(s(s(y'')), s(s(x''))) -> IFGCD(le(x'', y''), s(s(y'')), s(s(x'')))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Narrowing Transformation


Dependency Pairs:

GCD(s(s(y'')), s(s(x''))) -> IFGCD(le(x'', y''), s(s(y'')), s(s(x'')))
GCD(s(0), s(s(x''))) -> IFGCD(false, s(0), s(s(x'')))
IFGCD(true, s(x), s(y)) -> GCD(minus(x, y), s(y))
GCD(s(x'), s(0)) -> IFGCD(true, s(x'), s(0))
IFGCD(false, s(x), s(y)) -> GCD(minus(y, x), s(x))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(x), s(y)) -> GCD(minus(x, y), s(y))
two new Dependency Pairs are created:

IFGCD(true, s(x''), s(0)) -> GCD(x'', s(0))
IFGCD(true, s(s(x'')), s(s(y''))) -> GCD(minus(x'', y''), s(s(y'')))

The transformation is resulting in two new DP problems:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 11
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(x''), s(0)) -> GCD(x'', s(0))
GCD(s(x'), s(0)) -> IFGCD(true, s(x'), s(0))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(x''), s(0)) -> GCD(x'', s(0))
one new Dependency Pair is created:

IFGCD(true, s(s(x'''')), s(0)) -> GCD(s(x''''), s(0))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 13
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(s(x'''')), s(0)) -> GCD(s(x''''), s(0))
GCD(s(x'), s(0)) -> IFGCD(true, s(x'), s(0))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

GCD(s(x'), s(0)) -> IFGCD(true, s(x'), s(0))
one new Dependency Pair is created:

GCD(s(s(x'''''')), s(0)) -> IFGCD(true, s(s(x'''''')), s(0))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 15
Argument Filtering and Ordering


Dependency Pairs:

GCD(s(s(x'''''')), s(0)) -> IFGCD(true, s(s(x'''''')), s(0))
IFGCD(true, s(s(x'''')), s(0)) -> GCD(s(x''''), s(0))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pairs can be strictly oriented:

GCD(s(s(x'''''')), s(0)) -> IFGCD(true, s(s(x'''''')), s(0))
IFGCD(true, s(s(x'''')), s(0)) -> GCD(s(x''''), s(0))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
{true, s} > GCD > IFGCD > 0

resulting in one new DP problem.
Used Argument Filtering System:
IFGCD(x1, x2, x3) -> IFGCD(x1, x2, x3)
GCD(x1, x2) -> GCD(x1, x2)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 20
Dependency Graph


Dependency Pair:


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 12
Narrowing Transformation


Dependency Pairs:

IFGCD(true, s(s(x'')), s(s(y''))) -> GCD(minus(x'', y''), s(s(y'')))
GCD(s(0), s(s(x''))) -> IFGCD(false, s(0), s(s(x'')))
IFGCD(false, s(x), s(y)) -> GCD(minus(y, x), s(x))
GCD(s(s(y'')), s(s(x''))) -> IFGCD(le(x'', y''), s(s(y'')), s(s(x'')))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(false, s(x), s(y)) -> GCD(minus(y, x), s(x))
two new Dependency Pairs are created:

IFGCD(false, s(0), s(y')) -> GCD(y', s(0))
IFGCD(false, s(s(y'')), s(s(x''))) -> GCD(minus(x'', y''), s(s(y'')))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 14
Narrowing Transformation


Dependency Pairs:

IFGCD(false, s(s(y'')), s(s(x''))) -> GCD(minus(x'', y''), s(s(y'')))
GCD(s(s(y'')), s(s(x''))) -> IFGCD(le(x'', y''), s(s(y'')), s(s(x'')))
IFGCD(true, s(s(x'')), s(s(y''))) -> GCD(minus(x'', y''), s(s(y'')))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(y'')), s(s(x''))) -> IFGCD(le(x'', y''), s(s(y'')), s(s(x'')))
three new Dependency Pairs are created:

GCD(s(s(y''')), s(s(0))) -> IFGCD(true, s(s(y''')), s(s(0)))
GCD(s(s(0)), s(s(s(x')))) -> IFGCD(false, s(s(0)), s(s(s(x'))))
GCD(s(s(s(y'))), s(s(s(x')))) -> IFGCD(le(x', y'), s(s(s(y'))), s(s(s(x'))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 16
Narrowing Transformation


Dependency Pairs:

GCD(s(s(s(y'))), s(s(s(x')))) -> IFGCD(le(x', y'), s(s(s(y'))), s(s(s(x'))))
GCD(s(s(0)), s(s(s(x')))) -> IFGCD(false, s(s(0)), s(s(s(x'))))
IFGCD(true, s(s(x'')), s(s(y''))) -> GCD(minus(x'', y''), s(s(y'')))
GCD(s(s(y''')), s(s(0))) -> IFGCD(true, s(s(y''')), s(s(0)))
IFGCD(false, s(s(y'')), s(s(x''))) -> GCD(minus(x'', y''), s(s(y'')))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(x'')), s(s(y''))) -> GCD(minus(x'', y''), s(s(y'')))
two new Dependency Pairs are created:

IFGCD(true, s(s(x''')), s(s(0))) -> GCD(x''', s(s(0)))
IFGCD(true, s(s(s(x'))), s(s(s(y')))) -> GCD(minus(x', y'), s(s(s(y'))))

The transformation is resulting in two new DP problems:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 17
Argument Filtering and Ordering


Dependency Pairs:

IFGCD(true, s(s(x''')), s(s(0))) -> GCD(x''', s(s(0)))
GCD(s(s(y''')), s(s(0))) -> IFGCD(true, s(s(y''')), s(s(0)))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pairs can be strictly oriented:

IFGCD(true, s(s(x''')), s(s(0))) -> GCD(x''', s(s(0)))
GCD(s(s(y''')), s(s(0))) -> IFGCD(true, s(s(y''')), s(s(0)))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
{GCD, 0, IFGCD} > s

resulting in one new DP problem.
Used Argument Filtering System:
GCD(x1, x2) -> GCD(x1, x2)
IFGCD(x1, x2, x3) -> IFGCD(x2)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 18
Narrowing Transformation


Dependency Pairs:

IFGCD(true, s(s(s(x'))), s(s(s(y')))) -> GCD(minus(x', y'), s(s(s(y'))))
GCD(s(s(0)), s(s(s(x')))) -> IFGCD(false, s(s(0)), s(s(s(x'))))
IFGCD(false, s(s(y'')), s(s(x''))) -> GCD(minus(x'', y''), s(s(y'')))
GCD(s(s(s(y'))), s(s(s(x')))) -> IFGCD(le(x', y'), s(s(s(y'))), s(s(s(x'))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(false, s(s(y'')), s(s(x''))) -> GCD(minus(x'', y''), s(s(y'')))
two new Dependency Pairs are created:

IFGCD(false, s(s(0)), s(s(x'''))) -> GCD(x''', s(s(0)))
IFGCD(false, s(s(s(y'))), s(s(s(x')))) -> GCD(minus(x', y'), s(s(s(y'))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 19
Narrowing Transformation


Dependency Pairs:

IFGCD(false, s(s(s(y'))), s(s(s(x')))) -> GCD(minus(x', y'), s(s(s(y'))))
GCD(s(s(s(y'))), s(s(s(x')))) -> IFGCD(le(x', y'), s(s(s(y'))), s(s(s(x'))))
IFGCD(true, s(s(s(x'))), s(s(s(y')))) -> GCD(minus(x', y'), s(s(s(y'))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(s(y'))), s(s(s(x')))) -> IFGCD(le(x', y'), s(s(s(y'))), s(s(s(x'))))
three new Dependency Pairs are created:

GCD(s(s(s(y''))), s(s(s(0)))) -> IFGCD(true, s(s(s(y''))), s(s(s(0))))
GCD(s(s(s(0))), s(s(s(s(x''))))) -> IFGCD(false, s(s(s(0))), s(s(s(s(x'')))))
GCD(s(s(s(s(y'')))), s(s(s(s(x''))))) -> IFGCD(le(x'', y''), s(s(s(s(y'')))), s(s(s(s(x'')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 22
Narrowing Transformation


Dependency Pairs:

GCD(s(s(s(s(y'')))), s(s(s(s(x''))))) -> IFGCD(le(x'', y''), s(s(s(s(y'')))), s(s(s(s(x'')))))
GCD(s(s(s(0))), s(s(s(s(x''))))) -> IFGCD(false, s(s(s(0))), s(s(s(s(x'')))))
IFGCD(true, s(s(s(x'))), s(s(s(y')))) -> GCD(minus(x', y'), s(s(s(y'))))
GCD(s(s(s(y''))), s(s(s(0)))) -> IFGCD(true, s(s(s(y''))), s(s(s(0))))
IFGCD(false, s(s(s(y'))), s(s(s(x')))) -> GCD(minus(x', y'), s(s(s(y'))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(s(x'))), s(s(s(y')))) -> GCD(minus(x', y'), s(s(s(y'))))
two new Dependency Pairs are created:

IFGCD(true, s(s(s(x''))), s(s(s(0)))) -> GCD(x'', s(s(s(0))))
IFGCD(true, s(s(s(s(x'')))), s(s(s(s(y''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))

The transformation is resulting in two new DP problems:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 23
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(s(s(x''))), s(s(s(0)))) -> GCD(x'', s(s(s(0))))
GCD(s(s(s(y''))), s(s(s(0)))) -> IFGCD(true, s(s(s(y''))), s(s(s(0))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(s(x''))), s(s(s(0)))) -> GCD(x'', s(s(s(0))))
one new Dependency Pair is created:

IFGCD(true, s(s(s(s(s(s(y'''')))))), s(s(s(0)))) -> GCD(s(s(s(y''''))), s(s(s(0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 25
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(s(s(y'''')))))), s(s(s(0)))) -> GCD(s(s(s(y''''))), s(s(s(0))))
GCD(s(s(s(y''))), s(s(s(0)))) -> IFGCD(true, s(s(s(y''))), s(s(s(0))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(s(y''))), s(s(s(0)))) -> IFGCD(true, s(s(s(y''))), s(s(s(0))))
one new Dependency Pair is created:

GCD(s(s(s(s(s(s(y'''''')))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(y'''''')))))), s(s(s(0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 27
Forward Instantiation Transformation


Dependency Pairs:

GCD(s(s(s(s(s(s(y'''''')))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(y'''''')))))), s(s(s(0))))
IFGCD(true, s(s(s(s(s(s(y'''')))))), s(s(s(0)))) -> GCD(s(s(s(y''''))), s(s(s(0))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(s(s(s(s(y'''')))))), s(s(s(0)))) -> GCD(s(s(s(y''''))), s(s(s(0))))
one new Dependency Pair is created:

IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''))))))))), s(s(s(0)))) -> GCD(s(s(s(s(s(s(y'''''''')))))), s(s(s(0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 29
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''))))))))), s(s(s(0)))) -> GCD(s(s(s(s(s(s(y'''''''')))))), s(s(s(0))))
GCD(s(s(s(s(s(s(y'''''')))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(y'''''')))))), s(s(s(0))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(s(s(s(s(y'''''')))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(y'''''')))))), s(s(s(0))))
one new Dependency Pair is created:

GCD(s(s(s(s(s(s(s(s(s(y''''''''''))))))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''''))))))))), s(s(s(0))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 32
Argument Filtering and Ordering


Dependency Pairs:

GCD(s(s(s(s(s(s(s(s(s(y''''''''''))))))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''''))))))))), s(s(s(0))))
IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''))))))))), s(s(s(0)))) -> GCD(s(s(s(s(s(s(y'''''''')))))), s(s(s(0))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pairs can be strictly oriented:

GCD(s(s(s(s(s(s(s(s(s(y''''''''''))))))))), s(s(s(0)))) -> IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''''))))))))), s(s(s(0))))
IFGCD(true, s(s(s(s(s(s(s(s(s(y''''''''))))))))), s(s(s(0)))) -> GCD(s(s(s(s(s(s(y'''''''')))))), s(s(s(0))))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
{GCD, 0, s, IFGCD} > true

resulting in one new DP problem.
Used Argument Filtering System:
IFGCD(x1, x2, x3) -> IFGCD(x1, x2, x3)
GCD(x1, x2) -> GCD(x1, x2)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 40
Dependency Graph


Dependency Pair:


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




Using the Dependency Graph resulted in no new DP problems.


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 24
Narrowing Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(x'')))), s(s(s(s(y''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))
GCD(s(s(s(0))), s(s(s(s(x''))))) -> IFGCD(false, s(s(s(0))), s(s(s(s(x'')))))
IFGCD(false, s(s(s(y'))), s(s(s(x')))) -> GCD(minus(x', y'), s(s(s(y'))))
GCD(s(s(s(s(y'')))), s(s(s(s(x''))))) -> IFGCD(le(x'', y''), s(s(s(s(y'')))), s(s(s(s(x'')))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(false, s(s(s(y'))), s(s(s(x')))) -> GCD(minus(x', y'), s(s(s(y'))))
two new Dependency Pairs are created:

IFGCD(false, s(s(s(0))), s(s(s(x'')))) -> GCD(x'', s(s(s(0))))
IFGCD(false, s(s(s(s(y'')))), s(s(s(s(x''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 26
Narrowing Transformation


Dependency Pairs:

IFGCD(false, s(s(s(s(y'')))), s(s(s(s(x''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))
GCD(s(s(s(s(y'')))), s(s(s(s(x''))))) -> IFGCD(le(x'', y''), s(s(s(s(y'')))), s(s(s(s(x'')))))
IFGCD(true, s(s(s(s(x'')))), s(s(s(s(y''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(s(s(y'')))), s(s(s(s(x''))))) -> IFGCD(le(x'', y''), s(s(s(s(y'')))), s(s(s(s(x'')))))
three new Dependency Pairs are created:

GCD(s(s(s(s(y''')))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(y''')))), s(s(s(s(0)))))
GCD(s(s(s(s(0)))), s(s(s(s(s(x')))))) -> IFGCD(false, s(s(s(s(0)))), s(s(s(s(s(x'))))))
GCD(s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> IFGCD(le(x', y'), s(s(s(s(s(y'))))), s(s(s(s(s(x'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 28
Narrowing Transformation


Dependency Pairs:

GCD(s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> IFGCD(le(x', y'), s(s(s(s(s(y'))))), s(s(s(s(s(x'))))))
GCD(s(s(s(s(0)))), s(s(s(s(s(x')))))) -> IFGCD(false, s(s(s(s(0)))), s(s(s(s(s(x'))))))
IFGCD(true, s(s(s(s(x'')))), s(s(s(s(y''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))
GCD(s(s(s(s(y''')))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(y''')))), s(s(s(s(0)))))
IFGCD(false, s(s(s(s(y'')))), s(s(s(s(x''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(s(s(x'')))), s(s(s(s(y''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))
two new Dependency Pairs are created:

IFGCD(true, s(s(s(s(x''')))), s(s(s(s(0))))) -> GCD(x''', s(s(s(s(0)))))
IFGCD(true, s(s(s(s(s(x'))))), s(s(s(s(s(y')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))

The transformation is resulting in two new DP problems:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 30
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(x''')))), s(s(s(s(0))))) -> GCD(x''', s(s(s(s(0)))))
GCD(s(s(s(s(y''')))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(y''')))), s(s(s(s(0)))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(s(s(x''')))), s(s(s(s(0))))) -> GCD(x''', s(s(s(s(0)))))
one new Dependency Pair is created:

IFGCD(true, s(s(s(s(s(s(s(s(y''''')))))))), s(s(s(s(0))))) -> GCD(s(s(s(s(y''''')))), s(s(s(s(0)))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 33
Forward Instantiation Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(s(s(s(s(y''''')))))))), s(s(s(s(0))))) -> GCD(s(s(s(s(y''''')))), s(s(s(s(0)))))
GCD(s(s(s(s(y''')))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(y''')))), s(s(s(s(0)))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Forward Instantiation SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(s(s(y''')))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(y''')))), s(s(s(s(0)))))
one new Dependency Pair is created:

GCD(s(s(s(s(s(s(s(s(y''''''')))))))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(s(s(s(s(y''''''')))))))), s(s(s(s(0)))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 35
Argument Filtering and Ordering


Dependency Pairs:

GCD(s(s(s(s(s(s(s(s(y''''''')))))))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(s(s(s(s(y''''''')))))))), s(s(s(s(0)))))
IFGCD(true, s(s(s(s(s(s(s(s(y''''')))))))), s(s(s(s(0))))) -> GCD(s(s(s(s(y''''')))), s(s(s(s(0)))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pairs can be strictly oriented:

GCD(s(s(s(s(s(s(s(s(y''''''')))))))), s(s(s(s(0))))) -> IFGCD(true, s(s(s(s(s(s(s(s(y''''''')))))))), s(s(s(s(0)))))
IFGCD(true, s(s(s(s(s(s(s(s(y''''')))))))), s(s(s(s(0))))) -> GCD(s(s(s(s(y''''')))), s(s(s(s(0)))))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
{GCD, 0, s, IFGCD} > true

resulting in one new DP problem.
Used Argument Filtering System:
IFGCD(x1, x2, x3) -> IFGCD(x1, x2, x3)
GCD(x1, x2) -> GCD(x1, x2)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 31
Narrowing Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(s(x'))))), s(s(s(s(s(y')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))
GCD(s(s(s(s(0)))), s(s(s(s(s(x')))))) -> IFGCD(false, s(s(s(s(0)))), s(s(s(s(s(x'))))))
IFGCD(false, s(s(s(s(y'')))), s(s(s(s(x''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))
GCD(s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> IFGCD(le(x', y'), s(s(s(s(s(y'))))), s(s(s(s(s(x'))))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(false, s(s(s(s(y'')))), s(s(s(s(x''))))) -> GCD(minus(x'', y''), s(s(s(s(y'')))))
two new Dependency Pairs are created:

IFGCD(false, s(s(s(s(0)))), s(s(s(s(x'''))))) -> GCD(x''', s(s(s(s(0)))))
IFGCD(false, s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 34
Narrowing Transformation


Dependency Pairs:

IFGCD(false, s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))
GCD(s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> IFGCD(le(x', y'), s(s(s(s(s(y'))))), s(s(s(s(s(x'))))))
IFGCD(true, s(s(s(s(s(x'))))), s(s(s(s(s(y')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

GCD(s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> IFGCD(le(x', y'), s(s(s(s(s(y'))))), s(s(s(s(s(x'))))))
three new Dependency Pairs are created:

GCD(s(s(s(s(s(y''))))), s(s(s(s(s(0)))))) -> IFGCD(true, s(s(s(s(s(y''))))), s(s(s(s(s(0))))))
GCD(s(s(s(s(s(0))))), s(s(s(s(s(s(x''))))))) -> IFGCD(false, s(s(s(s(s(0))))), s(s(s(s(s(s(x'')))))))
GCD(s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x''))))))) -> IFGCD(le(x'', y''), s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x'')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 36
Narrowing Transformation


Dependency Pairs:

GCD(s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x''))))))) -> IFGCD(le(x'', y''), s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x'')))))))
GCD(s(s(s(s(s(0))))), s(s(s(s(s(s(x''))))))) -> IFGCD(false, s(s(s(s(s(0))))), s(s(s(s(s(s(x'')))))))
IFGCD(true, s(s(s(s(s(x'))))), s(s(s(s(s(y')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))
GCD(s(s(s(s(s(y''))))), s(s(s(s(s(0)))))) -> IFGCD(true, s(s(s(s(s(y''))))), s(s(s(s(s(0))))))
IFGCD(false, s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(true, s(s(s(s(s(x'))))), s(s(s(s(s(y')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))
two new Dependency Pairs are created:

IFGCD(true, s(s(s(s(s(x''))))), s(s(s(s(s(0)))))) -> GCD(x'', s(s(s(s(s(0))))))
IFGCD(true, s(s(s(s(s(s(x'')))))), s(s(s(s(s(s(y''))))))) -> GCD(minus(x'', y''), s(s(s(s(s(s(y'')))))))

The transformation is resulting in two new DP problems:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 37
Argument Filtering and Ordering


Dependency Pairs:

IFGCD(true, s(s(s(s(s(x''))))), s(s(s(s(s(0)))))) -> GCD(x'', s(s(s(s(s(0))))))
GCD(s(s(s(s(s(y''))))), s(s(s(s(s(0)))))) -> IFGCD(true, s(s(s(s(s(y''))))), s(s(s(s(s(0))))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




The following dependency pairs can be strictly oriented:

IFGCD(true, s(s(s(s(s(x''))))), s(s(s(s(s(0)))))) -> GCD(x'', s(s(s(s(s(0))))))
GCD(s(s(s(s(s(y''))))), s(s(s(s(s(0)))))) -> IFGCD(true, s(s(s(s(s(y''))))), s(s(s(s(s(0))))))


There are no usable rules for innermost w.r.t. to the AFS that need to be oriented.
Used ordering: Lexicographic Path Order with Non-Strict Precedence with Quasi Precedence:
{GCD, 0, s, IFGCD} > true

resulting in one new DP problem.
Used Argument Filtering System:
IFGCD(x1, x2, x3) -> IFGCD(x1, x2, x3)
GCD(x1, x2) -> GCD(x1)
s(x1) -> s(x1)


   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 38
Narrowing Transformation


Dependency Pairs:

IFGCD(true, s(s(s(s(s(s(x'')))))), s(s(s(s(s(s(y''))))))) -> GCD(minus(x'', y''), s(s(s(s(s(s(y'')))))))
GCD(s(s(s(s(s(0))))), s(s(s(s(s(s(x''))))))) -> IFGCD(false, s(s(s(s(s(0))))), s(s(s(s(s(s(x'')))))))
IFGCD(false, s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))
GCD(s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x''))))))) -> IFGCD(le(x'', y''), s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x'')))))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost




On this DP problem, a Narrowing SCC transformation can be performed.
As a result of transforming the rule

IFGCD(false, s(s(s(s(s(y'))))), s(s(s(s(s(x')))))) -> GCD(minus(x', y'), s(s(s(s(s(y'))))))
two new Dependency Pairs are created:

IFGCD(false, s(s(s(s(s(0))))), s(s(s(s(s(x'')))))) -> GCD(x'', s(s(s(s(s(0))))))
IFGCD(false, s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x''))))))) -> GCD(minus(x'', y''), s(s(s(s(s(s(y'')))))))

The transformation is resulting in one new DP problem:



   R
DPs
       →DP Problem 1
FwdInst
       →DP Problem 2
FwdInst
       →DP Problem 3
Nar
           →DP Problem 10
Nar
             ...
               →DP Problem 39
Remaining Obligation(s)




The following remains to be proven:
Dependency Pairs:

IFGCD(false, s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x''))))))) -> GCD(minus(x'', y''), s(s(s(s(s(s(y'')))))))
GCD(s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x''))))))) -> IFGCD(le(x'', y''), s(s(s(s(s(s(y'')))))), s(s(s(s(s(s(x'')))))))
IFGCD(true, s(s(s(s(s(s(x'')))))), s(s(s(s(s(s(y''))))))) -> GCD(minus(x'', y''), s(s(s(s(s(s(y'')))))))


Rules:


le(0, y) -> true
le(s(x), 0) -> false
le(s(x), s(y)) -> le(x, y)
minus(x, 0) -> x
minus(s(x), s(y)) -> minus(x, y)
gcd(0, y) -> y
gcd(s(x), 0) -> s(x)
gcd(s(x), s(y)) -> ifgcd(le(y, x), s(x), s(y))
ifgcd(true, s(x), s(y)) -> gcd(minus(x, y), s(y))
ifgcd(false, s(x), s(y)) -> gcd(minus(y, x), s(x))


Strategy:

innermost



Innermost Termination of R could not be shown.
Duration:
0:48 minutes