Term Rewriting System R:
[x]
f(f(x, a), a) -> f(f(f(a, f(a, a)), a), x)
Termination of R to be shown.
R
↳Dependency Pair Analysis
R contains the following Dependency Pairs:
F(f(x, a), a) -> F(f(f(a, f(a, a)), a), x)
F(f(x, a), a) -> F(f(a, f(a, a)), a)
F(f(x, a), a) -> F(a, f(a, a))
F(f(x, a), a) -> F(a, a)
Furthermore, R contains one SCC.
R
↳DPs
→DP Problem 1
↳Semantic Labelling
Dependency Pair:
F(f(x, a), a) -> F(f(f(a, f(a, a)), a), x)
Rule:
f(f(x, a), a) -> f(f(f(a, f(a, a)), a), x)
Using Semantic Labelling, the DP problem could be transformed. The following model was found:
F(x0, x1) | = 0 |
f(x0, x1) | = 0 |
a | = 0 |
From the dependency graph we obtain 1 (labeled) SCCs which each result in correspondingDP problem.
R
↳DPs
→DP Problem 1
↳SemLab
→DP Problem 2
↳Modular Removal of Rules
Dependency Pair:
F00(f00(x, a), a) -> F00(f00(f00(a, f00(a, a)), a), x)
Rules:
f00(f00(x, a), a) -> f00(f00(f00(a, f00(a, a)), a), x)
f00(f10(x, a), a) -> f01(f00(f00(a, f00(a, a)), a), x)
We have the following set of usable rules:
none
To remove rules and DPs from this DP problem we used the following monotonic and CE-compatible order: Polynomial ordering.
Polynomial interpretation:
POL(F_00(x1, x2)) | = 1 + x1 + x2 |
POL(f_00(x1, x2)) | = x1 + x2 |
POL(a) | = 0 |
We have the following set D of usable symbols: {F00, f00, a}
No Dependency Pairs can be deleted.
2 non usable rules have been deleted.
The result of this processor delivers one new DP problem.
R
↳DPs
→DP Problem 1
↳SemLab
→DP Problem 2
↳MRR
...
→DP Problem 3
↳Unlabel
Dependency Pair:
F00(f00(x, a), a) -> F00(f00(f00(a, f00(a, a)), a), x)
Rule:
none
Removed all semantic labels.
R
↳DPs
→DP Problem 1
↳SemLab
→DP Problem 2
↳MRR
...
→DP Problem 4
↳Instantiation Transformation
Dependency Pair:
F(f(x, a), a) -> F(f(f(a, f(a, a)), a), x)
Rule:
none
On this DP problem, an Instantiation SCC transformation can be performed.
As a result of transforming the rule
F(f(x, a), a) -> F(f(f(a, f(a, a)), a), x)
one new Dependency Pair
is created:
F(f(f(a, f(a, a)), a), a) -> F(f(f(a, f(a, a)), a), f(a, f(a, a)))
The transformation is resulting in no new DP problems.
Termination of R successfully shown.
Duration:
0:00 minutes