(0) Obligation:

The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(1, n^1).

The TRS R consists of the following rules:

g(0, f(x, x)) → x
g(x, s(y)) → g(f(x, y), 0)
g(s(x), y) → g(f(x, y), 0)
g(f(x, y), 0) → f(g(x, 0), g(y, 0))

Rewrite Strategy: FULL

(1) RcToIrcProof (BOTH BOUNDS(ID, ID) transformation)

Converted rc-obligation to irc-obligation.

As the TRS does not nest defined symbols, we have rc = irc.

(2) Obligation:

The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(1, n^1).

The TRS R consists of the following rules:

g(0, f(x, x)) → x
g(x, s(y)) → g(f(x, y), 0)
g(s(x), y) → g(f(x, y), 0)
g(f(x, y), 0) → f(g(x, 0), g(y, 0))

Rewrite Strategy: INNERMOST

(3) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted Cpx (relative) TRS to CDT

(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(0, f(z0, z0)) → z0
g(z0, s(z1)) → g(f(z0, z1), 0)
g(s(z0), z1) → g(f(z0, z1), 0)
g(f(z0, z1), 0) → f(g(z0, 0), g(z1, 0))
Tuples:

G(0, f(z0, z0)) → c
G(z0, s(z1)) → c1(G(f(z0, z1), 0))
G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
S tuples:

G(0, f(z0, z0)) → c
G(z0, s(z1)) → c1(G(f(z0, z1), 0))
G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
K tuples:none
Defined Rule Symbols:

g

Defined Pair Symbols:

G

Compound Symbols:

c, c1, c2, c3

(5) CdtLeafRemovalProof (ComplexityIfPolyImplication transformation)

G(z0, s(z1)) → c1(G(f(z0, z1), 0))
Removed 1 trailing nodes:

G(0, f(z0, z0)) → c

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(0, f(z0, z0)) → z0
g(z0, s(z1)) → g(f(z0, z1), 0)
g(s(z0), z1) → g(f(z0, z1), 0)
g(f(z0, z1), 0) → f(g(z0, 0), g(z1, 0))
Tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
S tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
K tuples:none
Defined Rule Symbols:

g

Defined Pair Symbols:

G

Compound Symbols:

c2, c3

(7) CdtUsableRulesProof (EQUIVALENT transformation)

The following rules are not usable and were removed:

g(0, f(z0, z0)) → z0
g(z0, s(z1)) → g(f(z0, z1), 0)
g(s(z0), z1) → g(f(z0, z1), 0)
g(f(z0, z1), 0) → f(g(z0, 0), g(z1, 0))

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:none
Tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
S tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
K tuples:none
Defined Rule Symbols:none

Defined Pair Symbols:

G

Compound Symbols:

c2, c3

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

G(s(z0), z1) → c2(G(f(z0, z1), 0))
We considered the (Usable) Rules:none
And the Tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(0) = 0
POL(G(x1, x2)) = x1 + x2
POL(c2(x1)) = x1
POL(c3(x1, x2)) = x1 + x2
POL(f(x1, x2)) = x1 + x2
POL(s(x1)) = [1] + x1

(10) Obligation:

Complexity Dependency Tuples Problem
Rules:none
Tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
S tuples:

G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
K tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
Defined Rule Symbols:none

Defined Pair Symbols:

G

Compound Symbols:

c2, c3

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
We considered the (Usable) Rules:none
And the Tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(0) = 0
POL(G(x1, x2)) = [3] + [3]x1 + [3]x2
POL(c2(x1)) = x1
POL(c3(x1, x2)) = x1 + x2
POL(f(x1, x2)) = [3] + x1 + x2
POL(s(x1)) = [3] + x1

(12) Obligation:

Complexity Dependency Tuples Problem
Rules:none
Tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
S tuples:none
K tuples:

G(s(z0), z1) → c2(G(f(z0, z1), 0))
G(f(z0, z1), 0) → c3(G(z0, 0), G(z1, 0))
Defined Rule Symbols:none

Defined Pair Symbols:

G

Compound Symbols:

c2, c3

(13) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty