### (0) Obligation:

The Runtime Complexity (full) of the given

*CpxTRS* could be proven to be

BOUNDS(1, n^1).

The TRS R consists of the following rules:

++(nil, y) → y

++(x, nil) → x

++(.(x, y), z) → .(x, ++(y, z))

++(++(x, y), z) → ++(x, ++(y, z))

Rewrite Strategy: FULL

### (1) NestedDefinedSymbolProof (BOTH BOUNDS(ID, ID) transformation)

The TRS does not nest defined symbols.

Hence, the left-hand sides of the following rules are not basic-reachable and can be removed:

++(++(x, y), z) → ++(x, ++(y, z))

### (2) Obligation:

The Runtime Complexity (full) of the given

*CpxTRS* could be proven to be

BOUNDS(1, n^1).

The TRS R consists of the following rules:

++(.(x, y), z) → .(x, ++(y, z))

++(nil, y) → y

++(x, nil) → x

Rewrite Strategy: FULL

### (3) RcToIrcProof (BOTH BOUNDS(ID, ID) transformation)

Converted rc-obligation to irc-obligation.

As the TRS does not nest defined symbols, we have rc = irc.

### (4) Obligation:

The Runtime Complexity (innermost) of the given

*CpxTRS* could be proven to be

BOUNDS(1, n^1).

The TRS R consists of the following rules:

++(.(x, y), z) → .(x, ++(y, z))

++(nil, y) → y

++(x, nil) → x

Rewrite Strategy: INNERMOST

### (5) CpxTrsMatchBoundsTAProof (EQUIVALENT transformation)

A linear upper bound on the runtime complexity of the TRS R could be shown with a Match-Bound[TAB_LEFTLINEAR,TAB_NONLEFTLINEAR] (for contructor-based start-terms) of 1.

The compatible tree automaton used to show the Match-Boundedness (for constructor-based start-terms) is represented by:

final states : [1]

transitions:

.0(0, 0) → 0

nil0() → 0

++0(0, 0) → 1

++1(0, 0) → 2

.1(0, 2) → 1

.1(0, 2) → 2

0 → 1

0 → 2

### (6) BOUNDS(1, n^1)