We consider the following Problem:

  Strict Trs: {g(x, a(), b()) -> g(b(), b(), a())}
  StartTerms: basic terms
  Strategy: innermost

Certificate: YES(?,O(n^1))

Proof:
  We consider the following Problem:
  
    Strict Trs: {g(x, a(), b()) -> g(b(), b(), a())}
    StartTerms: basic terms
    Strategy: innermost
  
  Certificate: YES(?,O(n^1))
  
  Proof:
    The weightgap principle applies, where following rules are oriented strictly:
    
    TRS Component: {g(x, a(), b()) -> g(b(), b(), a())}
    
    Interpretation of nonconstant growth:
    -------------------------------------
      The following argument positions are usable:
        Uargs(g) = {}
      We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
      Interpretation Functions:
       g(x1, x2, x3) = [0 0] x1 + [0 0] x2 + [0 1] x3 + [1]
                       [0 0]      [0 0]      [0 0]      [1]
       a() = [0]
             [0]
       b() = [0]
             [2]
    
    The strictly oriented rules are moved into the weak component.
    
    We consider the following Problem:
    
      Weak Trs: {g(x, a(), b()) -> g(b(), b(), a())}
      StartTerms: basic terms
      Strategy: innermost
    
    Certificate: YES(O(1),O(1))
    
    Proof:
      We consider the following Problem:
      
        Weak Trs: {g(x, a(), b()) -> g(b(), b(), a())}
        StartTerms: basic terms
        Strategy: innermost
      
      Certificate: YES(O(1),O(1))
      
      Proof:
        Empty rules are trivially bounded

Hurray, we answered YES(?,O(n^1))