(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

g(a) → g(b)
bf(a, a)
f(a, a) → g(d)

Rewrite Strategy: INNERMOST

(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted CpxTRS to CDT

(2) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(a) → g(b)
bf(a, a)
f(a, a) → g(d)
Tuples:

G(a) → c(G(b), B)
Bc1(F(a, a))
F(a, a) → c2(G(d))
S tuples:

G(a) → c(G(b), B)
Bc1(F(a, a))
F(a, a) → c2(G(d))
K tuples:none
Defined Rule Symbols:

g, b, f

Defined Pair Symbols:

G, B, F

Compound Symbols:

c, c1, c2

(3) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID) transformation)

Removed 2 trailing nodes:

Bc1(F(a, a))
F(a, a) → c2(G(d))

(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(a) → g(b)
bf(a, a)
f(a, a) → g(d)
Tuples:

G(a) → c(G(b), B)
S tuples:

G(a) → c(G(b), B)
K tuples:none
Defined Rule Symbols:

g, b, f

Defined Pair Symbols:

G

Compound Symbols:

c

(5) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing tuple parts

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(a) → g(b)
bf(a, a)
f(a, a) → g(d)
Tuples:

G(a) → c(G(b))
S tuples:

G(a) → c(G(b))
K tuples:none
Defined Rule Symbols:

g, b, f

Defined Pair Symbols:

G

Compound Symbols:

c

(7) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

G(a) → c(G(b))
We considered the (Usable) Rules:

bf(a, a)
f(a, a) → g(d)
And the Tuples:

G(a) → c(G(b))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(G(x1)) = [4]x1   
POL(a) = [4]   
POL(b) = 0   
POL(c(x1)) = x1   
POL(d) = 0   
POL(f(x1, x2)) = 0   
POL(g(x1)) = [3]x1   

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:

g(a) → g(b)
bf(a, a)
f(a, a) → g(d)
Tuples:

G(a) → c(G(b))
S tuples:none
K tuples:

G(a) → c(G(b))
Defined Rule Symbols:

g, b, f

Defined Pair Symbols:

G

Compound Symbols:

c

(9) SIsEmptyProof (EQUIVALENT transformation)

The set S is empty

(10) BOUNDS(O(1), O(1))