The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(O(1), O(n^1)).

(0) Obligation:

Runtime Complexity TRS:
The TRS R consists of the following rules:

a__and(true, X) → mark(X)
a__and(false, Y) → false
a__if(true, X, Y) → mark(X)
a__if(false, X, Y) → mark(Y)
a__add(0, X) → mark(X)
a__add(s(X), Y) → s(add(X, Y))
a__first(0, X) → nil
a__first(s(X), cons(Y, Z)) → cons(Y, first(X, Z))
a__from(X) → cons(X, from(s(X)))
mark(and(X1, X2)) → a__and(mark(X1), X2)
mark(if(X1, X2, X3)) → a__if(mark(X1), X2, X3)
mark(add(X1, X2)) → a__add(mark(X1), X2)
mark(first(X1, X2)) → a__first(mark(X1), mark(X2))
mark(from(X)) → a__from(X)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(X)) → s(X)
mark(nil) → nil
mark(cons(X1, X2)) → cons(X1, X2)
a__and(X1, X2) → and(X1, X2)
a__if(X1, X2, X3) → if(X1, X2, X3)
a__add(X1, X2) → add(X1, X2)
a__first(X1, X2) → first(X1, X2)
a__from(X) → from(X)

Rewrite Strategy: INNERMOST

(1) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted CpxTRS to CDT

(2) Obligation:

Complexity Dependency Tuples Problem
Rules:

a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)

Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(A__FIRST(mark(z0), mark(z1)), MARK(z0), MARK(z1))
MARK(from(z0)) → c18(A__FROM(z0))

S tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(A__FIRST(mark(z0), mark(z1)), MARK(z0), MARK(z1))
MARK(from(z0)) → c18(A__FROM(z0))

K tuples:none
Defined Rule Symbols:

a__and, a__if, a__add, a__first, a__from, mark

Defined Pair Symbols:

A__AND, A__IF, A__ADD, MARK

Compound Symbols:

c, c3, c4, c6, c14, c15, c16, c17, c18

(3) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing nodes:

MARK(from(z0)) → c18(A__FROM(z0))

(4) Obligation:

Complexity Dependency Tuples Problem
Rules:

a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)

Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(A__FIRST(mark(z0), mark(z1)), MARK(z0), MARK(z1))

S tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(A__FIRST(mark(z0), mark(z1)), MARK(z0), MARK(z1))

K tuples:none
Defined Rule Symbols:

a__and, a__if, a__add, a__first, a__from, mark

Defined Pair Symbols:

A__AND, A__IF, A__ADD, MARK

Compound Symbols:

c, c3, c4, c6, c14, c15, c16, c17

(5) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing tuple parts

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)

Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

S tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

K tuples:none
Defined Rule Symbols:

a__and, a__if, a__add, a__first, a__from, mark

Defined Pair Symbols:

A__AND, A__IF, A__ADD, MARK

Compound Symbols:

c, c3, c4, c6, c14, c15, c16, c17

(7) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

A__AND(true, z0) → c(MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

We considered the (Usable) Rules:

mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)
a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)

And the Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

The order we found is given by the following interpretation:
Polynomial interpretation :

POL(0) = 0   
POL(A__ADD(x₁, x₂)) = [4]x₂   
POL(A__AND(x₁, x₂)) = [4] + [4]x₂   
POL(A__IF(x₁, x₂, x₃)) = [4]x₂ + [4]x₃   
POL(MARK(x₁)) = [4]x₁   
POL(a__add(x₁, x₂)) = [3] + [3]x₂   
POL(a__and(x₁, x₂)) = [5] + [5]x₁ + [3]x₂   
POL(a__first(x₁, x₂)) = [3] + [3]x₁   
POL(a__from(x₁)) = [2] + [5]x₁   
POL(a__if(x₁, x₂, x₃)) = [3] + [3]x₁ + [2]x₂ + [5]x₃   
POL(add(x₁, x₂)) = x₁ + x₂   
POL(and(x₁, x₂)) = [1] + x₁ + x₂   
POL(c(x₁)) = x₁   
POL(c14(x₁, x₂)) = x₁ + x₂   
POL(c15(x₁, x₂)) = x₁ + x₂   
POL(c16(x₁, x₂)) = x₁ + x₂   
POL(c17(x₁, x₂)) = x₁ + x₂   
POL(c3(x₁)) = x₁   
POL(c4(x₁)) = x₁   
POL(c6(x₁)) = x₁   
POL(cons(x₁, x₂)) = [3]   
POL(false) = 0   
POL(first(x₁, x₂)) = [5] + x₁ + x₂   
POL(from(x₁)) = [3]   
POL(if(x₁, x₂, x₃)) = x₁ + x₂ + x₃   
POL(mark(x₁)) = x₁   
POL(nil) = [5]   
POL(s(x₁)) = [3]   
POL(true) = 0   

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:

a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)

Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

S tuples:

A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))

K tuples:

A__AND(true, z0) → c(MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

Defined Rule Symbols:

a__and, a__if, a__add, a__first, a__from, mark

Defined Pair Symbols:

A__AND, A__IF, A__ADD, MARK

Compound Symbols:

c, c3, c4, c6, c14, c15, c16, c17

(9) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))

We considered the (Usable) Rules:

mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)
a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)

And the Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

The order we found is given by the following interpretation:
Polynomial interpretation :

POL(0) = 0   
POL(A__ADD(x₁, x₂)) = [4]x₂   
POL(A__AND(x₁, x₂)) = [4]x₂   
POL(A__IF(x₁, x₂, x₃)) = [2] + [4]x₂ + [4]x₃   
POL(MARK(x₁)) = [4]x₁   
POL(a__add(x₁, x₂)) = [5] + [5]x₂   
POL(a__and(x₁, x₂)) = [3] + [5]x₁ + [2]x₂   
POL(a__first(x₁, x₂)) = [3] + [3]x₁ + x₂   
POL(a__from(x₁)) = [3] + [3]x₁   
POL(a__if(x₁, x₂, x₃)) = [3] + [3]x₁ + [4]x₂ + [3]x₃   
POL(add(x₁, x₂)) = x₁ + x₂   
POL(and(x₁, x₂)) = [4] + x₁ + x₂   
POL(c(x₁)) = x₁   
POL(c14(x₁, x₂)) = x₁ + x₂   
POL(c15(x₁, x₂)) = x₁ + x₂   
POL(c16(x₁, x₂)) = x₁ + x₂   
POL(c17(x₁, x₂)) = x₁ + x₂   
POL(c3(x₁)) = x₁   
POL(c4(x₁)) = x₁   
POL(c6(x₁)) = x₁   
POL(cons(x₁, x₂)) = [3]   
POL(false) = 0   
POL(first(x₁, x₂)) = [1] + x₁ + x₂   
POL(from(x₁)) = [3]   
POL(if(x₁, x₂, x₃)) = [4] + x₁ + x₂ + x₃   
POL(mark(x₁)) = [3]x₁   
POL(nil) = [3]   
POL(s(x₁)) = [3]   
POL(true) = 0   

(10) Obligation:

Complexity Dependency Tuples Problem
Rules:

a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)

Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

S tuples:

A__ADD(0, z0) → c6(MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))

K tuples:

A__AND(true, z0) → c(MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))

Defined Rule Symbols:

a__and, a__if, a__add, a__first, a__from, mark

Defined Pair Symbols:

A__AND, A__IF, A__ADD, MARK

Compound Symbols:

c, c3, c4, c6, c14, c15, c16, c17

(11) CdtPolyRedPairProof (UPPER BOUND (ADD(O(n^1))) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))

We considered the (Usable) Rules:

mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)
a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)

And the Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

The order we found is given by the following interpretation:
Polynomial interpretation :

POL(0) = 0   
POL(A__ADD(x₁, x₂)) = [4]x₂   
POL(A__AND(x₁, x₂)) = [3] + [4]x₂   
POL(A__IF(x₁, x₂, x₃)) = [4] + [4]x₂ + [4]x₃   
POL(MARK(x₁)) = [4]x₁   
POL(a__add(x₁, x₂)) = [4] + [2]x₁ + [3]x₂   
POL(a__and(x₁, x₂)) = [5] + [3]x₁ + [3]x₂   
POL(a__first(x₁, x₂)) = [2] + [2]x₁ + [2]x₂   
POL(a__from(x₁)) = [3] + [3]x₁   
POL(a__if(x₁, x₂, x₃)) = [4] + [3]x₁ + [2]x₂ + [4]x₃   
POL(add(x₁, x₂)) = [4] + x₁ + x₂   
POL(and(x₁, x₂)) = [1] + x₁ + x₂   
POL(c(x₁)) = x₁   
POL(c14(x₁, x₂)) = x₁ + x₂   
POL(c15(x₁, x₂)) = x₁ + x₂   
POL(c16(x₁, x₂)) = x₁ + x₂   
POL(c17(x₁, x₂)) = x₁ + x₂   
POL(c3(x₁)) = x₁   
POL(c4(x₁)) = x₁   
POL(c6(x₁)) = x₁   
POL(cons(x₁, x₂)) = [2]   
POL(false) = [2]   
POL(first(x₁, x₂)) = x₁ + x₂   
POL(from(x₁)) = [3]   
POL(if(x₁, x₂, x₃)) = [1] + x₁ + x₂ + x₃   
POL(mark(x₁)) = 0   
POL(nil) = [5]   
POL(s(x₁)) = [3]   
POL(true) = [4]   

(12) Obligation:

Complexity Dependency Tuples Problem
Rules:

a__and(true, z0) → mark(z0)
a__and(false, z0) → false
a__and(z0, z1) → and(z0, z1)
a__if(true, z0, z1) → mark(z0)
a__if(false, z0, z1) → mark(z1)
a__if(z0, z1, z2) → if(z0, z1, z2)
a__add(0, z0) → mark(z0)
a__add(s(z0), z1) → s(add(z0, z1))
a__add(z0, z1) → add(z0, z1)
a__first(0, z0) → nil
a__first(s(z0), cons(z1, z2)) → cons(z1, first(z0, z2))
a__first(z0, z1) → first(z0, z1)
a__from(z0) → cons(z0, from(s(z0)))
a__from(z0) → from(z0)
mark(and(z0, z1)) → a__and(mark(z0), z1)
mark(if(z0, z1, z2)) → a__if(mark(z0), z1, z2)
mark(add(z0, z1)) → a__add(mark(z0), z1)
mark(first(z0, z1)) → a__first(mark(z0), mark(z1))
mark(from(z0)) → a__from(z0)
mark(true) → true
mark(false) → false
mark(0) → 0
mark(s(z0)) → s(z0)
mark(nil) → nil
mark(cons(z0, z1)) → cons(z0, z1)

Tuples:

A__AND(true, z0) → c(MARK(z0))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

S tuples:

A__ADD(0, z0) → c6(MARK(z0))

K tuples:

A__AND(true, z0) → c(MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))
A__IF(true, z0, z1) → c3(MARK(z0))
A__IF(false, z0, z1) → c4(MARK(z1))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))

Defined Rule Symbols:

a__and, a__if, a__add, a__first, a__from, mark

Defined Pair Symbols:

A__AND, A__IF, A__ADD, MARK

Compound Symbols:

c, c3, c4, c6, c14, c15, c16, c17

(13) CdtKnowledgeProof (EQUIVALENT transformation)

The following tuples could be moved from S to K by knowledge propagation:

A__ADD(0, z0) → c6(MARK(z0))
MARK(and(z0, z1)) → c14(A__AND(mark(z0), z1), MARK(z0))
MARK(if(z0, z1, z2)) → c15(A__IF(mark(z0), z1, z2), MARK(z0))
MARK(add(z0, z1)) → c16(A__ADD(mark(z0), z1), MARK(z0))
MARK(first(z0, z1)) → c17(MARK(z0), MARK(z1))

Now S is empty

(14) BOUNDS(O(1), O(1))