We consider the following Problem:

  Strict Trs:
    {  d(x) -> e(u(x))
     , d(u(x)) -> c(x)
     , c(u(x)) -> b(x)
     , v(e(x)) -> x
     , b(u(x)) -> a(e(x))}
  StartTerms: basic terms
  Strategy: innermost

Certificate: YES(?,O(n^1))

Proof:
  We consider the following Problem:
  
    Strict Trs:
      {  d(x) -> e(u(x))
       , d(u(x)) -> c(x)
       , c(u(x)) -> b(x)
       , v(e(x)) -> x
       , b(u(x)) -> a(e(x))}
    StartTerms: basic terms
    Strategy: innermost
  
  Certificate: YES(?,O(n^1))
  
  Proof:
    The weightgap principle applies, where following rules are oriented strictly:
    
    TRS Component: {b(u(x)) -> a(e(x))}
    
    Interpretation of nonconstant growth:
    -------------------------------------
      The following argument positions are usable:
        Uargs(d) = {}, Uargs(e) = {}, Uargs(u) = {}, Uargs(c) = {},
        Uargs(b) = {}, Uargs(v) = {}, Uargs(a) = {}
      We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
      Interpretation Functions:
       d(x1) = [0 0] x1 + [1]
               [0 0]      [1]
       e(x1) = [0 0] x1 + [1]
               [1 0]      [1]
       u(x1) = [0 0] x1 + [0]
               [0 0]      [0]
       c(x1) = [0 0] x1 + [1]
               [0 0]      [1]
       b(x1) = [0 0] x1 + [1]
               [0 0]      [1]
       v(x1) = [0 1] x1 + [0]
               [0 0]      [1]
       a(x1) = [0 0] x1 + [0]
               [0 0]      [1]
    
    The strictly oriented rules are moved into the weak component.
    
    We consider the following Problem:
    
      Strict Trs:
        {  d(x) -> e(u(x))
         , d(u(x)) -> c(x)
         , c(u(x)) -> b(x)
         , v(e(x)) -> x}
      Weak Trs: {b(u(x)) -> a(e(x))}
      StartTerms: basic terms
      Strategy: innermost
    
    Certificate: YES(?,O(n^1))
    
    Proof:
      The weightgap principle applies, where following rules are oriented strictly:
      
      TRS Component: {c(u(x)) -> b(x)}
      
      Interpretation of nonconstant growth:
      -------------------------------------
        The following argument positions are usable:
          Uargs(d) = {}, Uargs(e) = {}, Uargs(u) = {}, Uargs(c) = {},
          Uargs(b) = {}, Uargs(v) = {}, Uargs(a) = {}
        We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
        Interpretation Functions:
         d(x1) = [0 0] x1 + [1]
                 [0 0]      [1]
         e(x1) = [0 0] x1 + [1]
                 [1 0]      [1]
         u(x1) = [0 0] x1 + [0]
                 [0 0]      [0]
         c(x1) = [0 0] x1 + [1]
                 [0 0]      [1]
         b(x1) = [0 0] x1 + [0]
                 [0 0]      [1]
         v(x1) = [0 1] x1 + [0]
                 [0 0]      [1]
         a(x1) = [0 0] x1 + [0]
                 [0 0]      [1]
      
      The strictly oriented rules are moved into the weak component.
      
      We consider the following Problem:
      
        Strict Trs:
          {  d(x) -> e(u(x))
           , d(u(x)) -> c(x)
           , v(e(x)) -> x}
        Weak Trs:
          {  c(u(x)) -> b(x)
           , b(u(x)) -> a(e(x))}
        StartTerms: basic terms
        Strategy: innermost
      
      Certificate: YES(?,O(n^1))
      
      Proof:
        The weightgap principle applies, where following rules are oriented strictly:
        
        TRS Component: {d(u(x)) -> c(x)}
        
        Interpretation of nonconstant growth:
        -------------------------------------
          The following argument positions are usable:
            Uargs(d) = {}, Uargs(e) = {}, Uargs(u) = {}, Uargs(c) = {},
            Uargs(b) = {}, Uargs(v) = {}, Uargs(a) = {}
          We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
          Interpretation Functions:
           d(x1) = [0 0] x1 + [1]
                   [0 0]      [1]
           e(x1) = [0 0] x1 + [1]
                   [1 0]      [1]
           u(x1) = [0 0] x1 + [0]
                   [0 0]      [0]
           c(x1) = [0 0] x1 + [0]
                   [0 0]      [1]
           b(x1) = [0 0] x1 + [0]
                   [0 0]      [1]
           v(x1) = [0 1] x1 + [0]
                   [0 0]      [1]
           a(x1) = [0 0] x1 + [0]
                   [0 0]      [1]
        
        The strictly oriented rules are moved into the weak component.
        
        We consider the following Problem:
        
          Strict Trs:
            {  d(x) -> e(u(x))
             , v(e(x)) -> x}
          Weak Trs:
            {  d(u(x)) -> c(x)
             , c(u(x)) -> b(x)
             , b(u(x)) -> a(e(x))}
          StartTerms: basic terms
          Strategy: innermost
        
        Certificate: YES(?,O(n^1))
        
        Proof:
          The weightgap principle applies, where following rules are oriented strictly:
          
          TRS Component: {d(x) -> e(u(x))}
          
          Interpretation of nonconstant growth:
          -------------------------------------
            The following argument positions are usable:
              Uargs(d) = {}, Uargs(e) = {}, Uargs(u) = {}, Uargs(c) = {},
              Uargs(b) = {}, Uargs(v) = {}, Uargs(a) = {}
            We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
            Interpretation Functions:
             d(x1) = [0 0] x1 + [3]
                     [0 0]      [1]
             e(x1) = [0 0] x1 + [1]
                     [1 0]      [1]
             u(x1) = [0 0] x1 + [0]
                     [0 0]      [0]
             c(x1) = [0 0] x1 + [1]
                     [0 0]      [1]
             b(x1) = [0 0] x1 + [1]
                     [0 0]      [1]
             v(x1) = [0 1] x1 + [0]
                     [0 0]      [1]
             a(x1) = [0 0] x1 + [1]
                     [0 0]      [1]
          
          The strictly oriented rules are moved into the weak component.
          
          We consider the following Problem:
          
            Strict Trs: {v(e(x)) -> x}
            Weak Trs:
              {  d(x) -> e(u(x))
               , d(u(x)) -> c(x)
               , c(u(x)) -> b(x)
               , b(u(x)) -> a(e(x))}
            StartTerms: basic terms
            Strategy: innermost
          
          Certificate: YES(?,O(n^1))
          
          Proof:
            The weightgap principle applies, where following rules are oriented strictly:
            
            TRS Component: {v(e(x)) -> x}
            
            Interpretation of nonconstant growth:
            -------------------------------------
              The following argument positions are usable:
                Uargs(d) = {}, Uargs(e) = {}, Uargs(u) = {}, Uargs(c) = {},
                Uargs(b) = {}, Uargs(v) = {}, Uargs(a) = {}
              We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
              Interpretation Functions:
               d(x1) = [1 0] x1 + [1]
                       [0 1]      [1]
               e(x1) = [1 0] x1 + [0]
                       [0 1]      [0]
               u(x1) = [0 0] x1 + [0]
                       [0 0]      [0]
               c(x1) = [0 0] x1 + [1]
                       [0 0]      [1]
               b(x1) = [0 0] x1 + [1]
                       [0 0]      [1]
               v(x1) = [1 0] x1 + [1]
                       [0 1]      [1]
               a(x1) = [0 0] x1 + [1]
                       [0 0]      [1]
            
            The strictly oriented rules are moved into the weak component.
            
            We consider the following Problem:
            
              Weak Trs:
                {  v(e(x)) -> x
                 , d(x) -> e(u(x))
                 , d(u(x)) -> c(x)
                 , c(u(x)) -> b(x)
                 , b(u(x)) -> a(e(x))}
              StartTerms: basic terms
              Strategy: innermost
            
            Certificate: YES(O(1),O(1))
            
            Proof:
              We consider the following Problem:
              
                Weak Trs:
                  {  v(e(x)) -> x
                   , d(x) -> e(u(x))
                   , d(u(x)) -> c(x)
                   , c(u(x)) -> b(x)
                   , b(u(x)) -> a(e(x))}
                StartTerms: basic terms
                Strategy: innermost
              
              Certificate: YES(O(1),O(1))
              
              Proof:
                Empty rules are trivially bounded

Hurray, we answered YES(?,O(n^1))