We consider the following Problem:
Strict Trs:
{ ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X)
, u21(ackout(X), Y) -> u22(ackin(Y, X))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(?,O(n^1))
Proof:
We consider the following Problem:
Strict Trs:
{ ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X)
, u21(ackout(X), Y) -> u22(ackin(Y, X))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(?,O(n^1))
Proof:
The weightgap principle applies, where following rules are oriented strictly:
TRS Component: {u21(ackout(X), Y) -> u22(ackin(Y, X))}
Interpretation of nonconstant growth:
-------------------------------------
The following argument positions are usable:
Uargs(ackin) = {}, Uargs(s) = {}, Uargs(u21) = {1},
Uargs(ackout) = {}, Uargs(u22) = {1}
We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
Interpretation Functions:
ackin(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
[0 0] [0 0] [1]
s(x1) = [0 0] x1 + [0]
[0 0] [0]
u21(x1, x2) = [1 0] x1 + [0 0] x2 + [0]
[0 0] [1 1] [1]
ackout(x1) = [0 0] x1 + [2]
[0 0] [0]
u22(x1) = [1 0] x1 + [0]
[0 0] [1]
The strictly oriented rules are moved into the weak component.
We consider the following Problem:
Strict Trs: {ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X)}
Weak Trs: {u21(ackout(X), Y) -> u22(ackin(Y, X))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(?,O(n^1))
Proof:
The weightgap principle applies, where following rules are oriented strictly:
TRS Component: {ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X)}
Interpretation of nonconstant growth:
-------------------------------------
The following argument positions are usable:
Uargs(ackin) = {}, Uargs(s) = {}, Uargs(u21) = {1},
Uargs(ackout) = {}, Uargs(u22) = {1}
We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
Interpretation Functions:
ackin(x1, x2) = [0 0] x1 + [1 1] x2 + [0]
[0 0] [0 0] [1]
s(x1) = [0 1] x1 + [3]
[1 0] [2]
u21(x1, x2) = [1 0] x1 + [0 0] x2 + [0]
[0 0] [0 0] [1]
ackout(x1) = [1 1] x1 + [0]
[0 0] [0]
u22(x1) = [1 0] x1 + [0]
[0 0] [1]
The strictly oriented rules are moved into the weak component.
We consider the following Problem:
Weak Trs:
{ ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X)
, u21(ackout(X), Y) -> u22(ackin(Y, X))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(O(1),O(1))
Proof:
We consider the following Problem:
Weak Trs:
{ ackin(s(X), s(Y)) -> u21(ackin(s(X), Y), X)
, u21(ackout(X), Y) -> u22(ackin(Y, X))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(O(1),O(1))
Proof:
Empty rules are trivially bounded
Hurray, we answered YES(?,O(n^1))