We consider the following Problem:

  Strict Trs:
    {  f(a()) -> f(c(a()))
     , f(c(X)) -> X
     , f(c(a())) -> f(d(b()))
     , f(a()) -> f(d(a()))
     , f(d(X)) -> X
     , f(c(b())) -> f(d(a()))
     , e(g(X)) -> e(X)}
  StartTerms: basic terms
  Strategy: innermost

Certificate: YES(?,O(n^1))

Proof:
  We consider the following Problem:
  
    Strict Trs:
      {  f(a()) -> f(c(a()))
       , f(c(X)) -> X
       , f(c(a())) -> f(d(b()))
       , f(a()) -> f(d(a()))
       , f(d(X)) -> X
       , f(c(b())) -> f(d(a()))
       , e(g(X)) -> e(X)}
    StartTerms: basic terms
    Strategy: innermost
  
  Certificate: YES(?,O(n^1))
  
  Proof:
    The weightgap principle applies, where following rules are oriented strictly:
    
    TRS Component: {f(c(b())) -> f(d(a()))}
    
    Interpretation of nonconstant growth:
    -------------------------------------
      The following argument positions are usable:
        Uargs(f) = {}, Uargs(c) = {}, Uargs(d) = {}, Uargs(e) = {},
        Uargs(g) = {}
      We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
      Interpretation Functions:
       f(x1) = [1 0] x1 + [1]
               [1 0]      [1]
       a() = [0]
             [0]
       c(x1) = [1 0] x1 + [0]
               [0 0]      [0]
       d(x1) = [1 0] x1 + [0]
               [0 0]      [0]
       b() = [2]
             [0]
       e(x1) = [0 0] x1 + [1]
               [0 0]      [1]
       g(x1) = [0 0] x1 + [0]
               [0 0]      [0]
    
    The strictly oriented rules are moved into the weak component.
    
    We consider the following Problem:
    
      Strict Trs:
        {  f(a()) -> f(c(a()))
         , f(c(X)) -> X
         , f(c(a())) -> f(d(b()))
         , f(a()) -> f(d(a()))
         , f(d(X)) -> X
         , e(g(X)) -> e(X)}
      Weak Trs: {f(c(b())) -> f(d(a()))}
      StartTerms: basic terms
      Strategy: innermost
    
    Certificate: YES(?,O(n^1))
    
    Proof:
      The weightgap principle applies, where following rules are oriented strictly:
      
      TRS Component: {f(c(a())) -> f(d(b()))}
      
      Interpretation of nonconstant growth:
      -------------------------------------
        The following argument positions are usable:
          Uargs(f) = {}, Uargs(c) = {}, Uargs(d) = {}, Uargs(e) = {},
          Uargs(g) = {}
        We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
        Interpretation Functions:
         f(x1) = [1 1] x1 + [1]
                 [0 0]      [1]
         a() = [0]
               [0]
         c(x1) = [1 0] x1 + [0]
                 [0 0]      [2]
         d(x1) = [1 0] x1 + [0]
                 [0 0]      [0]
         b() = [0]
               [0]
         e(x1) = [0 0] x1 + [1]
                 [0 0]      [1]
         g(x1) = [0 0] x1 + [0]
                 [0 0]      [0]
      
      The strictly oriented rules are moved into the weak component.
      
      We consider the following Problem:
      
        Strict Trs:
          {  f(a()) -> f(c(a()))
           , f(c(X)) -> X
           , f(a()) -> f(d(a()))
           , f(d(X)) -> X
           , e(g(X)) -> e(X)}
        Weak Trs:
          {  f(c(a())) -> f(d(b()))
           , f(c(b())) -> f(d(a()))}
        StartTerms: basic terms
        Strategy: innermost
      
      Certificate: YES(?,O(n^1))
      
      Proof:
        The weightgap principle applies, where following rules are oriented strictly:
        
        TRS Component:
          {  f(a()) -> f(c(a()))
           , f(a()) -> f(d(a()))}
        
        Interpretation of nonconstant growth:
        -------------------------------------
          The following argument positions are usable:
            Uargs(f) = {}, Uargs(c) = {}, Uargs(d) = {}, Uargs(e) = {},
            Uargs(g) = {}
          We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
          Interpretation Functions:
           f(x1) = [1 1] x1 + [0]
                   [0 0]      [1]
           a() = [0]
                 [2]
           c(x1) = [1 0] x1 + [1]
                   [0 0]      [0]
           d(x1) = [1 0] x1 + [1]
                   [0 0]      [0]
           b() = [0]
                 [0]
           e(x1) = [0 0] x1 + [1]
                   [0 0]      [1]
           g(x1) = [0 0] x1 + [0]
                   [0 0]      [0]
        
        The strictly oriented rules are moved into the weak component.
        
        We consider the following Problem:
        
          Strict Trs:
            {  f(c(X)) -> X
             , f(d(X)) -> X
             , e(g(X)) -> e(X)}
          Weak Trs:
            {  f(a()) -> f(c(a()))
             , f(a()) -> f(d(a()))
             , f(c(a())) -> f(d(b()))
             , f(c(b())) -> f(d(a()))}
          StartTerms: basic terms
          Strategy: innermost
        
        Certificate: YES(?,O(n^1))
        
        Proof:
          The weightgap principle applies, where following rules are oriented strictly:
          
          TRS Component: {e(g(X)) -> e(X)}
          
          Interpretation of nonconstant growth:
          -------------------------------------
            The following argument positions are usable:
              Uargs(f) = {}, Uargs(c) = {}, Uargs(d) = {}, Uargs(e) = {},
              Uargs(g) = {}
            We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
            Interpretation Functions:
             f(x1) = [1 0] x1 + [0]
                     [1 0]      [1]
             a() = [0]
                   [0]
             c(x1) = [1 0] x1 + [0]
                     [1 0]      [0]
             d(x1) = [1 0] x1 + [0]
                     [0 0]      [0]
             b() = [0]
                   [0]
             e(x1) = [0 1] x1 + [2]
                     [0 0]      [0]
             g(x1) = [0 0] x1 + [0]
                     [0 1]      [2]
          
          The strictly oriented rules are moved into the weak component.
          
          We consider the following Problem:
          
            Strict Trs:
              {  f(c(X)) -> X
               , f(d(X)) -> X}
            Weak Trs:
              {  e(g(X)) -> e(X)
               , f(a()) -> f(c(a()))
               , f(a()) -> f(d(a()))
               , f(c(a())) -> f(d(b()))
               , f(c(b())) -> f(d(a()))}
            StartTerms: basic terms
            Strategy: innermost
          
          Certificate: YES(?,O(n^1))
          
          Proof:
            The weightgap principle applies, where following rules are oriented strictly:
            
            TRS Component: {f(d(X)) -> X}
            
            Interpretation of nonconstant growth:
            -------------------------------------
              The following argument positions are usable:
                Uargs(f) = {}, Uargs(c) = {}, Uargs(d) = {}, Uargs(e) = {},
                Uargs(g) = {}
              We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
              Interpretation Functions:
               f(x1) = [1 0] x1 + [1]
                       [0 1]      [1]
               a() = [0]
                     [0]
               c(x1) = [1 0] x1 + [0]
                       [0 0]      [0]
               d(x1) = [1 0] x1 + [0]
                       [0 1]      [0]
               b() = [0]
                     [0]
               e(x1) = [0 0] x1 + [1]
                       [0 0]      [1]
               g(x1) = [0 0] x1 + [0]
                       [0 0]      [0]
            
            The strictly oriented rules are moved into the weak component.
            
            We consider the following Problem:
            
              Strict Trs: {f(c(X)) -> X}
              Weak Trs:
                {  f(d(X)) -> X
                 , e(g(X)) -> e(X)
                 , f(a()) -> f(c(a()))
                 , f(a()) -> f(d(a()))
                 , f(c(a())) -> f(d(b()))
                 , f(c(b())) -> f(d(a()))}
              StartTerms: basic terms
              Strategy: innermost
            
            Certificate: YES(?,O(n^1))
            
            Proof:
              The weightgap principle applies, where following rules are oriented strictly:
              
              TRS Component: {f(c(X)) -> X}
              
              Interpretation of nonconstant growth:
              -------------------------------------
                The following argument positions are usable:
                  Uargs(f) = {}, Uargs(c) = {}, Uargs(d) = {}, Uargs(e) = {},
                  Uargs(g) = {}
                We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
                Interpretation Functions:
                 f(x1) = [1 0] x1 + [1]
                         [0 1]      [1]
                 a() = [0]
                       [0]
                 c(x1) = [1 0] x1 + [0]
                         [0 1]      [0]
                 d(x1) = [1 0] x1 + [0]
                         [0 1]      [0]
                 b() = [0]
                       [0]
                 e(x1) = [0 0] x1 + [1]
                         [0 0]      [1]
                 g(x1) = [0 0] x1 + [0]
                         [0 0]      [0]
              
              The strictly oriented rules are moved into the weak component.
              
              We consider the following Problem:
              
                Weak Trs:
                  {  f(c(X)) -> X
                   , f(d(X)) -> X
                   , e(g(X)) -> e(X)
                   , f(a()) -> f(c(a()))
                   , f(a()) -> f(d(a()))
                   , f(c(a())) -> f(d(b()))
                   , f(c(b())) -> f(d(a()))}
                StartTerms: basic terms
                Strategy: innermost
              
              Certificate: YES(O(1),O(1))
              
              Proof:
                We consider the following Problem:
                
                  Weak Trs:
                    {  f(c(X)) -> X
                     , f(d(X)) -> X
                     , e(g(X)) -> e(X)
                     , f(a()) -> f(c(a()))
                     , f(a()) -> f(d(a()))
                     , f(c(a())) -> f(d(b()))
                     , f(c(b())) -> f(d(a()))}
                  StartTerms: basic terms
                  Strategy: innermost
                
                Certificate: YES(O(1),O(1))
                
                Proof:
                  Empty rules are trivially bounded

Hurray, we answered YES(?,O(n^1))