We consider the following Problem:

  Strict Trs:
    {  f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
     , trunc(0()) -> 0()
     , trunc(s(0())) -> 0()
     , trunc(s(s(x))) -> s(s(trunc(x)))
     , gt(0(), v) -> false()
     , gt(s(u), 0()) -> true()
     , gt(s(u), s(v)) -> gt(u, v)}
  StartTerms: basic terms
  Strategy: innermost

Certificate: YES(?,O(n^1))

Proof:
  We consider the following Problem:
  
    Strict Trs:
      {  f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
       , trunc(0()) -> 0()
       , trunc(s(0())) -> 0()
       , trunc(s(s(x))) -> s(s(trunc(x)))
       , gt(0(), v) -> false()
       , gt(s(u), 0()) -> true()
       , gt(s(u), s(v)) -> gt(u, v)}
    StartTerms: basic terms
    Strategy: innermost
  
  Certificate: YES(?,O(n^1))
  
  Proof:
    The weightgap principle applies, where following rules are oriented strictly:
    
    TRS Component:
      {  trunc(0()) -> 0()
       , trunc(s(0())) -> 0()
       , gt(0(), v) -> false()
       , gt(s(u), 0()) -> true()}
    
    Interpretation of nonconstant growth:
    -------------------------------------
      The following argument positions are usable:
        Uargs(f) = {1, 2}, Uargs(gt) = {}, Uargs(trunc) = {},
        Uargs(s) = {1}
      We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
      Interpretation Functions:
       f(x1, x2, x3) = [1 0] x1 + [1 0] x2 + [0 0] x3 + [1]
                       [0 0]      [0 0]      [1 0]      [1]
       true() = [0]
                [0]
       gt(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
                    [0 0]      [0 0]      [1]
       trunc(x1) = [0 0] x1 + [3]
                   [0 0]      [1]
       s(x1) = [1 0] x1 + [0]
               [0 1]      [2]
       0() = [0]
             [0]
       false() = [0]
                 [0]
    
    The strictly oriented rules are moved into the weak component.
    
    We consider the following Problem:
    
      Strict Trs:
        {  f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
         , trunc(s(s(x))) -> s(s(trunc(x)))
         , gt(s(u), s(v)) -> gt(u, v)}
      Weak Trs:
        {  trunc(0()) -> 0()
         , trunc(s(0())) -> 0()
         , gt(0(), v) -> false()
         , gt(s(u), 0()) -> true()}
      StartTerms: basic terms
      Strategy: innermost
    
    Certificate: YES(?,O(n^1))
    
    Proof:
      The weightgap principle applies, where following rules are oriented strictly:
      
      TRS Component: {f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))}
      
      Interpretation of nonconstant growth:
      -------------------------------------
        The following argument positions are usable:
          Uargs(f) = {1, 2}, Uargs(gt) = {}, Uargs(trunc) = {},
          Uargs(s) = {1}
        We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
        Interpretation Functions:
         f(x1, x2, x3) = [1 1] x1 + [1 0] x2 + [0 2] x3 + [0]
                         [0 0]      [0 0]      [0 0]      [1]
         true() = [1]
                  [3]
         gt(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
                      [0 0]      [0 1]      [1]
         trunc(x1) = [0 0] x1 + [0]
                     [0 0]      [2]
         s(x1) = [1 0] x1 + [0]
                 [0 0]      [0]
         0() = [0]
               [2]
         false() = [0]
                   [0]
      
      The strictly oriented rules are moved into the weak component.
      
      We consider the following Problem:
      
        Strict Trs:
          {  trunc(s(s(x))) -> s(s(trunc(x)))
           , gt(s(u), s(v)) -> gt(u, v)}
        Weak Trs:
          {  f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
           , trunc(0()) -> 0()
           , trunc(s(0())) -> 0()
           , gt(0(), v) -> false()
           , gt(s(u), 0()) -> true()}
        StartTerms: basic terms
        Strategy: innermost
      
      Certificate: YES(?,O(n^1))
      
      Proof:
        The weightgap principle applies, where following rules are oriented strictly:
        
        TRS Component: {gt(s(u), s(v)) -> gt(u, v)}
        
        Interpretation of nonconstant growth:
        -------------------------------------
          The following argument positions are usable:
            Uargs(f) = {1, 2}, Uargs(gt) = {}, Uargs(trunc) = {},
            Uargs(s) = {1}
          We have the following EDA-non-satisfying and IDA(1)-non-satisfying matrix interpretation:
          Interpretation Functions:
           f(x1, x2, x3) = [1 0] x1 + [1 0] x2 + [0 0] x3 + [3]
                           [0 0]      [0 0]      [0 0]      [1]
           true() = [2]
                    [0]
           gt(x1, x2) = [1 0] x1 + [0 0] x2 + [2]
                        [0 0]      [0 0]      [1]
           trunc(x1) = [0 0] x1 + [0]
                       [0 0]      [1]
           s(x1) = [1 0] x1 + [2]
                   [0 0]      [0]
           0() = [0]
                 [0]
           false() = [0]
                     [0]
        
        The strictly oriented rules are moved into the weak component.
        
        We consider the following Problem:
        
          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
          Weak Trs:
            {  gt(s(u), s(v)) -> gt(u, v)
             , f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
             , trunc(0()) -> 0()
             , trunc(s(0())) -> 0()
             , gt(0(), v) -> false()
             , gt(s(u), 0()) -> true()}
          StartTerms: basic terms
          Strategy: innermost
        
        Certificate: YES(?,O(n^1))
        
        Proof:
          We consider the following Problem:
          
            Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
            Weak Trs:
              {  gt(s(u), s(v)) -> gt(u, v)
               , f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
               , trunc(0()) -> 0()
               , trunc(s(0())) -> 0()
               , gt(0(), v) -> false()
               , gt(s(u), 0()) -> true()}
            StartTerms: basic terms
            Strategy: innermost
          
          Certificate: YES(?,O(n^1))
          
          Proof:
            We have computed the following dependency pairs
            
              Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
              Weak DPs:
                {  gt^#(s(u), s(v)) -> gt^#(u, v)
                 , f^#(true(), x, y) -> f^#(gt(x, y), trunc(x), s(y))
                 , trunc^#(0()) -> c_4()
                 , trunc^#(s(0())) -> c_5()
                 , gt^#(0(), v) -> c_6()
                 , gt^#(s(u), 0()) -> c_7()}
            
            We consider the following Problem:
            
              Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
              Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
              Weak DPs:
                {  gt^#(s(u), s(v)) -> gt^#(u, v)
                 , f^#(true(), x, y) -> f^#(gt(x, y), trunc(x), s(y))
                 , trunc^#(0()) -> c_4()
                 , trunc^#(s(0())) -> c_5()
                 , gt^#(0(), v) -> c_6()
                 , gt^#(s(u), 0()) -> c_7()}
              Weak Trs:
                {  gt(s(u), s(v)) -> gt(u, v)
                 , f(true(), x, y) -> f(gt(x, y), trunc(x), s(y))
                 , trunc(0()) -> 0()
                 , trunc(s(0())) -> 0()
                 , gt(0(), v) -> false()
                 , gt(s(u), 0()) -> true()}
              StartTerms: basic terms
              Strategy: innermost
            
            Certificate: YES(?,O(n^1))
            
            Proof:
              We replace strict/weak-rules by the corresponding usable rules:
              
                Strict Usable Rules: {trunc(s(s(x))) -> s(s(trunc(x)))}
                Weak Usable Rules:
                  {  gt(s(u), s(v)) -> gt(u, v)
                   , trunc(0()) -> 0()
                   , trunc(s(0())) -> 0()
                   , gt(0(), v) -> false()
                   , gt(s(u), 0()) -> true()}
              
              We consider the following Problem:
              
                Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                Weak DPs:
                  {  gt^#(s(u), s(v)) -> gt^#(u, v)
                   , f^#(true(), x, y) -> f^#(gt(x, y), trunc(x), s(y))
                   , trunc^#(0()) -> c_4()
                   , trunc^#(s(0())) -> c_5()
                   , gt^#(0(), v) -> c_6()
                   , gt^#(s(u), 0()) -> c_7()}
                Weak Trs:
                  {  gt(s(u), s(v)) -> gt(u, v)
                   , trunc(0()) -> 0()
                   , trunc(s(0())) -> 0()
                   , gt(0(), v) -> false()
                   , gt(s(u), 0()) -> true()}
                StartTerms: basic terms
                Strategy: innermost
              
              Certificate: YES(?,O(n^1))
              
              Proof:
                We consider the following Problem:
                
                  Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                  Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                  Weak DPs:
                    {  gt^#(s(u), s(v)) -> gt^#(u, v)
                     , f^#(true(), x, y) -> f^#(gt(x, y), trunc(x), s(y))
                     , trunc^#(0()) -> c_4()
                     , trunc^#(s(0())) -> c_5()
                     , gt^#(0(), v) -> c_6()
                     , gt^#(s(u), 0()) -> c_7()}
                  Weak Trs:
                    {  gt(s(u), s(v)) -> gt(u, v)
                     , trunc(0()) -> 0()
                     , trunc(s(0())) -> 0()
                     , gt(0(), v) -> false()
                     , gt(s(u), 0()) -> true()}
                  StartTerms: basic terms
                  Strategy: innermost
                
                Certificate: YES(?,O(n^1))
                
                Proof:
                  We use following congruence DG for path analysis
                  
                  ->5:{1}                                                     [   YES(?,O(n^1))    ]
                     |
                     |->6:{4}                                                 [   YES(O(1),O(1))   ]
                     |
                     `->7:{5}                                                 [   YES(O(1),O(1))   ]
                  
                  ->2:{2}                                                     [      subsumed      ]
                     |
                     |->3:{6}                                                 [   YES(O(1),O(1))   ]
                     |
                     `->4:{7}                                                 [   YES(O(1),O(1))   ]
                  
                  ->1:{3}                                                     [   YES(O(1),O(1))   ]
                  
                  
                  Here dependency-pairs are as follows:
                  
                  Strict DPs:
                    {1: trunc^#(s(s(x))) -> trunc^#(x)}
                  WeakDPs DPs:
                    {  2: gt^#(s(u), s(v)) -> gt^#(u, v)
                     , 3: f^#(true(), x, y) -> f^#(gt(x, y), trunc(x), s(y))
                     , 4: trunc^#(0()) -> c_4()
                     , 5: trunc^#(s(0())) -> c_5()
                     , 6: gt^#(0(), v) -> c_6()
                     , 7: gt^#(s(u), 0()) -> c_7()}
                  
                  * Path 5:{1}: YES(?,O(n^1))
                    -------------------------
                    
                    We consider the following Problem:
                    
                      Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                      Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                      Weak Trs:
                        {  gt(s(u), s(v)) -> gt(u, v)
                         , trunc(0()) -> 0()
                         , trunc(s(0())) -> 0()
                         , gt(0(), v) -> false()
                         , gt(s(u), 0()) -> true()}
                      StartTerms: basic terms
                      Strategy: innermost
                    
                    Certificate: YES(?,O(n^1))
                    
                    Proof:
                      We consider the following Problem:
                      
                        Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                        Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                        Weak Trs:
                          {  gt(s(u), s(v)) -> gt(u, v)
                           , trunc(0()) -> 0()
                           , trunc(s(0())) -> 0()
                           , gt(0(), v) -> false()
                           , gt(s(u), 0()) -> true()}
                        StartTerms: basic terms
                        Strategy: innermost
                      
                      Certificate: YES(?,O(n^1))
                      
                      Proof:
                        We consider the following Problem:
                        
                          Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                          Weak Trs:
                            {  gt(s(u), s(v)) -> gt(u, v)
                             , trunc(0()) -> 0()
                             , trunc(s(0())) -> 0()
                             , gt(0(), v) -> false()
                             , gt(s(u), 0()) -> true()}
                          StartTerms: basic terms
                          Strategy: innermost
                        
                        Certificate: YES(?,O(n^1))
                        
                        Proof:
                          No rule is usable.
                          
                          We consider the following Problem:
                          
                            Strict DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                            StartTerms: basic terms
                            Strategy: innermost
                          
                          Certificate: YES(?,O(n^1))
                          
                          Proof:
                            The problem is match-bounded by 1.
                            The enriched problem is compatible with the following automaton:
                            {  s_0(5) -> 5
                             , trunc^#_0(5) -> 8
                             , trunc^#_1(5) -> 8}
                  
                  * Path 5:{1}->6:{4}: YES(O(1),O(1))
                    ---------------------------------
                    
                    We consider the following Problem:
                    
                      Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                      Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                      Weak Trs:
                        {  gt(s(u), s(v)) -> gt(u, v)
                         , trunc(0()) -> 0()
                         , trunc(s(0())) -> 0()
                         , gt(0(), v) -> false()
                         , gt(s(u), 0()) -> true()}
                      StartTerms: basic terms
                      Strategy: innermost
                    
                    Certificate: YES(O(1),O(1))
                    
                    Proof:
                      We consider the following Problem:
                      
                        Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                        Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                        Weak Trs:
                          {  gt(s(u), s(v)) -> gt(u, v)
                           , trunc(0()) -> 0()
                           , trunc(s(0())) -> 0()
                           , gt(0(), v) -> false()
                           , gt(s(u), 0()) -> true()}
                        StartTerms: basic terms
                        Strategy: innermost
                      
                      Certificate: YES(O(1),O(1))
                      
                      Proof:
                        We consider the following Problem:
                        
                          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                          Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                          Weak Trs:
                            {  gt(s(u), s(v)) -> gt(u, v)
                             , trunc(0()) -> 0()
                             , trunc(s(0())) -> 0()
                             , gt(0(), v) -> false()
                             , gt(s(u), 0()) -> true()}
                          StartTerms: basic terms
                          Strategy: innermost
                        
                        Certificate: YES(O(1),O(1))
                        
                        Proof:
                          No rule is usable.
                          
                          We consider the following Problem:
                          
                            Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                            StartTerms: basic terms
                            Strategy: innermost
                          
                          Certificate: YES(O(1),O(1))
                          
                          Proof:
                            Empty rules are trivially bounded
                  
                  * Path 5:{1}->7:{5}: YES(O(1),O(1))
                    ---------------------------------
                    
                    We consider the following Problem:
                    
                      Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                      Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                      Weak Trs:
                        {  gt(s(u), s(v)) -> gt(u, v)
                         , trunc(0()) -> 0()
                         , trunc(s(0())) -> 0()
                         , gt(0(), v) -> false()
                         , gt(s(u), 0()) -> true()}
                      StartTerms: basic terms
                      Strategy: innermost
                    
                    Certificate: YES(O(1),O(1))
                    
                    Proof:
                      We consider the following Problem:
                      
                        Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                        Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                        Weak Trs:
                          {  gt(s(u), s(v)) -> gt(u, v)
                           , trunc(0()) -> 0()
                           , trunc(s(0())) -> 0()
                           , gt(0(), v) -> false()
                           , gt(s(u), 0()) -> true()}
                        StartTerms: basic terms
                        Strategy: innermost
                      
                      Certificate: YES(O(1),O(1))
                      
                      Proof:
                        We consider the following Problem:
                        
                          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                          Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                          Weak Trs:
                            {  gt(s(u), s(v)) -> gt(u, v)
                             , trunc(0()) -> 0()
                             , trunc(s(0())) -> 0()
                             , gt(0(), v) -> false()
                             , gt(s(u), 0()) -> true()}
                          StartTerms: basic terms
                          Strategy: innermost
                        
                        Certificate: YES(O(1),O(1))
                        
                        Proof:
                          No rule is usable.
                          
                          We consider the following Problem:
                          
                            Weak DPs: {trunc^#(s(s(x))) -> trunc^#(x)}
                            StartTerms: basic terms
                            Strategy: innermost
                          
                          Certificate: YES(O(1),O(1))
                          
                          Proof:
                            Empty rules are trivially bounded
                  
                  * Path 2:{2}: subsumed
                    --------------------
                    
                    This path is subsumed by the proof of paths 2:{2}->4:{7},
                                                                2:{2}->3:{6}.
                  
                  * Path 2:{2}->3:{6}: YES(O(1),O(1))
                    ---------------------------------
                    
                    We consider the following Problem:
                    
                      Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                      Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                      Weak Trs:
                        {  gt(s(u), s(v)) -> gt(u, v)
                         , trunc(0()) -> 0()
                         , trunc(s(0())) -> 0()
                         , gt(0(), v) -> false()
                         , gt(s(u), 0()) -> true()}
                      StartTerms: basic terms
                      Strategy: innermost
                    
                    Certificate: YES(O(1),O(1))
                    
                    Proof:
                      We consider the following Problem:
                      
                        Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                        Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                        Weak Trs:
                          {  gt(s(u), s(v)) -> gt(u, v)
                           , trunc(0()) -> 0()
                           , trunc(s(0())) -> 0()
                           , gt(0(), v) -> false()
                           , gt(s(u), 0()) -> true()}
                        StartTerms: basic terms
                        Strategy: innermost
                      
                      Certificate: YES(O(1),O(1))
                      
                      Proof:
                        We consider the following Problem:
                        
                          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                          Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                          Weak Trs:
                            {  gt(s(u), s(v)) -> gt(u, v)
                             , trunc(0()) -> 0()
                             , trunc(s(0())) -> 0()
                             , gt(0(), v) -> false()
                             , gt(s(u), 0()) -> true()}
                          StartTerms: basic terms
                          Strategy: innermost
                        
                        Certificate: YES(O(1),O(1))
                        
                        Proof:
                          No rule is usable.
                          
                          We consider the following Problem:
                          
                            Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                            StartTerms: basic terms
                            Strategy: innermost
                          
                          Certificate: YES(O(1),O(1))
                          
                          Proof:
                            Empty rules are trivially bounded
                  
                  * Path 2:{2}->4:{7}: YES(O(1),O(1))
                    ---------------------------------
                    
                    We consider the following Problem:
                    
                      Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                      Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                      Weak Trs:
                        {  gt(s(u), s(v)) -> gt(u, v)
                         , trunc(0()) -> 0()
                         , trunc(s(0())) -> 0()
                         , gt(0(), v) -> false()
                         , gt(s(u), 0()) -> true()}
                      StartTerms: basic terms
                      Strategy: innermost
                    
                    Certificate: YES(O(1),O(1))
                    
                    Proof:
                      We consider the following Problem:
                      
                        Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                        Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                        Weak Trs:
                          {  gt(s(u), s(v)) -> gt(u, v)
                           , trunc(0()) -> 0()
                           , trunc(s(0())) -> 0()
                           , gt(0(), v) -> false()
                           , gt(s(u), 0()) -> true()}
                        StartTerms: basic terms
                        Strategy: innermost
                      
                      Certificate: YES(O(1),O(1))
                      
                      Proof:
                        We consider the following Problem:
                        
                          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                          Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                          Weak Trs:
                            {  gt(s(u), s(v)) -> gt(u, v)
                             , trunc(0()) -> 0()
                             , trunc(s(0())) -> 0()
                             , gt(0(), v) -> false()
                             , gt(s(u), 0()) -> true()}
                          StartTerms: basic terms
                          Strategy: innermost
                        
                        Certificate: YES(O(1),O(1))
                        
                        Proof:
                          No rule is usable.
                          
                          We consider the following Problem:
                          
                            Weak DPs: {gt^#(s(u), s(v)) -> gt^#(u, v)}
                            StartTerms: basic terms
                            Strategy: innermost
                          
                          Certificate: YES(O(1),O(1))
                          
                          Proof:
                            Empty rules are trivially bounded
                  
                  * Path 1:{3}: YES(O(1),O(1))
                    --------------------------
                    
                    We consider the following Problem:
                    
                      Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                      Weak Trs:
                        {  gt(s(u), s(v)) -> gt(u, v)
                         , trunc(0()) -> 0()
                         , trunc(s(0())) -> 0()
                         , gt(0(), v) -> false()
                         , gt(s(u), 0()) -> true()}
                      StartTerms: basic terms
                      Strategy: innermost
                    
                    Certificate: YES(O(1),O(1))
                    
                    Proof:
                      We consider the following Problem:
                      
                        Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                        Weak Trs:
                          {  gt(s(u), s(v)) -> gt(u, v)
                           , trunc(0()) -> 0()
                           , trunc(s(0())) -> 0()
                           , gt(0(), v) -> false()
                           , gt(s(u), 0()) -> true()}
                        StartTerms: basic terms
                        Strategy: innermost
                      
                      Certificate: YES(O(1),O(1))
                      
                      Proof:
                        We consider the following Problem:
                        
                          Strict Trs: {trunc(s(s(x))) -> s(s(trunc(x)))}
                          Weak Trs:
                            {  gt(s(u), s(v)) -> gt(u, v)
                             , trunc(0()) -> 0()
                             , trunc(s(0())) -> 0()
                             , gt(0(), v) -> false()
                             , gt(s(u), 0()) -> true()}
                          StartTerms: basic terms
                          Strategy: innermost
                        
                        Certificate: YES(O(1),O(1))
                        
                        Proof:
                          No rule is usable.
                          
                          We consider the following Problem:
                          
                            StartTerms: basic terms
                            Strategy: innermost
                          
                          Certificate: YES(O(1),O(1))
                          
                          Proof:
                            Empty rules are trivially bounded

Hurray, we answered YES(?,O(n^1))