Termination of the following Term Rewriting System could be proven:
Context-sensitive rewrite system:
The TRS R consists of the following rules:
2nd(cons(X, cons(Y, Z))) → Y
from(X) → cons(X, from(s(X)))
The replacement map contains the following entries:2nd: {1}
cons: {1}
from: {1}
s: {1}
↳ CSR
↳ CSRInnermostProof
Context-sensitive rewrite system:
The TRS R consists of the following rules:
2nd(cons(X, cons(Y, Z))) → Y
from(X) → cons(X, from(s(X)))
The replacement map contains the following entries:2nd: {1}
cons: {1}
from: {1}
s: {1}
The CSR is orthogonal. By [10] we can switch to innermost.
↳ CSR
↳ CSRInnermostProof
↳ CSR
↳ CSDependencyPairsProof
Context-sensitive rewrite system:
The TRS R consists of the following rules:
2nd(cons(X, cons(Y, Z))) → Y
from(X) → cons(X, from(s(X)))
The replacement map contains the following entries:2nd: {1}
cons: {1}
from: {1}
s: {1}
Innermost Strategy.
Using Improved CS-DPs we result in the following initial Q-CSDP problem.
↳ CSR
↳ CSRInnermostProof
↳ CSR
↳ CSDependencyPairsProof
↳ QCSDP
↳ QCSDependencyGraphProof
Q-restricted context-sensitive dependency pair problem:
The symbols in {2nd, from, s, 2ND, FROM} are replacing on all positions.
For all symbols f in {cons} we have µ(f) = {1}.
The symbols in {U} are not replacing on any position.
The collapsing dependency pairs are DPc:
2ND(cons(X, cons(Y, Z))) → Y
The hidden terms of R are:
from(s(X))
Every hiding context is built from:
s on positions {1}
from on positions {1}
Hence, the new unhiding pairs DPu are :
2ND(cons(X, cons(Y, Z))) → U(Y)
U(s(x_0)) → U(x_0)
U(from(x_0)) → U(x_0)
U(from(s(X))) → FROM(s(X))
The TRS R consists of the following rules:
2nd(cons(X, cons(Y, Z))) → Y
from(X) → cons(X, from(s(X)))
The set Q consists of the following terms:
2nd(cons(x0, cons(x1, x2)))
from(x0)
The approximation of the Context-Sensitive Dependency Graph contains 1 SCC with 2 less nodes.
↳ CSR
↳ CSRInnermostProof
↳ CSR
↳ CSDependencyPairsProof
↳ QCSDP
↳ QCSDependencyGraphProof
↳ QCSDP
↳ QCSDPSubtermProof
Q-restricted context-sensitive dependency pair problem:
The symbols in {2nd, from, s} are replacing on all positions.
For all symbols f in {cons} we have µ(f) = {1}.
The symbols in {U} are not replacing on any position.
The TRS P consists of the following rules:
U(s(x_0)) → U(x_0)
U(from(x_0)) → U(x_0)
The TRS R consists of the following rules:
2nd(cons(X, cons(Y, Z))) → Y
from(X) → cons(X, from(s(X)))
The set Q consists of the following terms:
2nd(cons(x0, cons(x1, x2)))
from(x0)
We use the subterm processor [20].
The following pairs can be oriented strictly and are deleted.
U(s(x_0)) → U(x_0)
U(from(x_0)) → U(x_0)
The remaining pairs can at least be oriented weakly.
none
Used ordering: Combined order from the following AFS and order.
U(x1) = x1
Subterm Order
↳ CSR
↳ CSRInnermostProof
↳ CSR
↳ CSDependencyPairsProof
↳ QCSDP
↳ QCSDependencyGraphProof
↳ QCSDP
↳ QCSDPSubtermProof
↳ QCSDP
↳ PIsEmptyProof
Q-restricted context-sensitive dependency pair problem:
The symbols in {2nd, from, s} are replacing on all positions.
For all symbols f in {cons} we have µ(f) = {1}.
The TRS P consists of the following rules:
none
The TRS R consists of the following rules:
2nd(cons(X, cons(Y, Z))) → Y
from(X) → cons(X, from(s(X)))
The set Q consists of the following terms:
2nd(cons(x0, cons(x1, x2)))
from(x0)
The TRS P is empty. Hence, there is no (P,Q,R,µ)-chain.