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The given Problem was:
a a b -> b c b a a a
a c ->
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A self-embedding rewrite structure for the given SRS is:
a a b a b c b b c b --(12)-> b c b b c b b c b a b c b a a b a b c b b c b a a a (#65546)
OC+OC at 20
OC: a a b a b c b b c --(11)-> b c b b c b b c b a b c b a a b a b c b a a (#13007)
OC+OC at 17
OC: a a b a b c b --(9)-> b c b b c b b c b a b c b a a b a a a (#5732)
OC+OC at 10
OC: a a b a b c b --(7)-> b c b b c b b c b a a a b c b a a a (#850)
OC+OC at 12
OC: a a b a b c --(6)-> b c b b c b b c b a a a a a (#275)
OC+OC at 6
OC: a a b a b c --(5)-> b c b b c b a a b a a (#155)
OC+OC at 3
OC: a a b a b c --(3)-> b c b a a b c b a a (#9)
OC+OC at 5
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a a b c --(2)-> b c b a a (#3)
OC+OC at 5
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a c --(1)-> (#2)
Rule
OC: a a b c --(2)-> b c b a a (#3)
OC+OC at 5
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a c --(1)-> (#2)
Rule
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a a b c --(2)-> b c b a a (#3)
OC+OC at 5
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a c --(1)-> (#2)
Rule
OC: a a b c --(2)-> b c b a a (#3)
OC+OC at 5
OC: a a b --(1)-> b c b a a a (#1)
Rule
OC: a c --(1)-> (#2)
Rule
OC: a a b --(1)-> b c b a a a (#1)
Rule
Hence, the SRS is non-terminating.